使用 Laravel Blade 显示来自 Postgres 的 JSON 数据

Question

我有一个 postgres 数据库，它有一个包含两列的 table（'id' 是主键，'data' 存储一个 JSONB 数据集标题、内容等）。

目前，我只能显示整个 table，或每个 'data'，但我无法从 'data' 中提取单个数据，即标题。

这是路线，我尝试将数据作为 json 提取，以及 json 解码：

Route::get('/home', function () {
    $articles = DB::table('articles')->get();
    $results = json_decode($articles, true);
    return view('home', compact('articles', 'results'));
});

home.blade.php 模板。我试过使用文章和结果来显示标题。我能得到的最好的是显示整个 table，但我无法调用标题：

@foreach ($results as $result)            
  <div>{{ $result->title }}</div>
@endforeach 

@foreach ($articles as $article)            
  <div>{{ $article->title }}</div>
@endforeach 

@foreach ($results as $result)            
  <div>{{$result['data']}}</div> //this shows the whole json object, posted below
@endforeach

 @foreach ($results as $result)            
  <div>{{$result['data']['title']}}</div> //I believe this should work, but I get Illegal String Offset 'title' as an error,
 @endforeach

我遇到的一些错误：

htmlspecialchars() expects parameter 1 to be string, array given
Array to string conversion
Illegal string offset 'title'
Something about calling something that's not there

这是 json object 在 json_decode 之后的样子（来自上面的 $result['data']）：

{"url": "http://omgili.com/ri/.wHSUbtEfZQrTHDoKYSJbjrpQN.N5MJgWJskXd50cUpWKooC_zdZBj5IfjtQ82V5YE9KjMI9MkoEoWsmLqcSDiWUKMSrDShx9H3vPUjRQuW0sylmueXyZg--", "text": "Cable companies are ove....", "uuid": "8c43aa206860570df0a86ff11f619235dea6e2bf", "title": "Cable companies are looking for ways to limit password sharing", "author": "theverge.com", "rating": null, "thread": {"url": "http://omgili.com/ri/.wHSUbtEfZQrTHDoKYSJbjrpQN.N5MJgWJskXd50cUpWKooC_zdZBj5IfjtQ82V5YE9KjMI9MkoEoWsmLqcSDiWUKMSrDShx9H3vPUjRQuW0sylmueXyZg--", "site": "theverge.com", "uuid": "8c43aa206860570df0a86ff11f619235dea6e2bf", "title": "Cable companies are looking for ways to limit password sharing", "social": {"vk": {"shares": 0}, "gplus": {"shares": 0}, "facebook": {"likes": 0, "shares": 0, "comments": 0}, "linkedin": {"shares": 0}, "pinterest": {"shares": 0}, "stumbledupon": {"shares": 0}}, "country": "US", "published": "2017-12-20T18:17:00.000+02:00", "site_full": "www.theverge.com", "site_type": "news", "main_image": "https://cdn.vox-cdn.com/thumbor/wCruRyorIkyClceG2T4Q0BsYk7Y=/0x73:1020x607/fit-in/1200x630/cdn.vox-cdn.com/assets/4562901/theverge1_1020.jpg", "spam_score": 0, "title_full": "Cable companies are looking for ways to limit password sharing - The Verge", "domain_rank": 496, "site_section": "http://www.theverge.com/tech/rss/index.xml", "replies_count": 0, "section_title": "The Verge - Tech Posts", "site_categories": ["media"], "performance_score": 0, "participants_count": 1}, "crawled": "2017-12-20T18:29:59.008+02:00", "entities": {"persons": [{"name": "rutledge", "sentiment": "none"}, {"name": "tom rutledge", "sentiment": "none"}], "locations": [], "organizations": [{"name": "netflix", "sentiment": "none"}, {"name": "bloomberg", "sentiment": "none"}, {"name": "viacom", "sentiment": "none"}, {"name": "ubs", "sentiment": "none"}, {"name": "espn", "sentiment": "none"}]}, "language": "english", "published": "2017-12-20T18:17:00.000+02:00", "highlightText": "", "ord_in_thread": 0, "external_links": [], "highlightTitle": ""}

Answer 1

您的代码的问题是当您从 Postgres 查询数据时，Eloquent return 您是 Collection 对象而不是 JSON 字符串。因此，行：

$results = json_decode($articles, true);

从来没有用过。由于 json_decode 函数仅适用于字符串（特别是 UTF8 编码字符串）。

您看到的错误是因为 $article->data 实际上没有被解析并且仍然是一个字符串。

当您将字符串视为数组时，会发生

Array to string conversion 和 Illegal string offset 错误。

基本上要parse/decode JSON 数据正确，你必须通过集合并手动转换它。您可以使用 Eloquent\Collection::map 函数将数据正确映射到关联数组：

$results = $articles->map(function($article){
   return [
      'id' => $article->id,
      'data' => json_decode($article->data, true)  
   ];
})

使用 Laravel Blade 显示来自 Postgres 的 JSON 数据

Displaying JSON Data From Postgres WIth Laravel Blade

php

json

postgresql

laravel

blade