如何聚合 sql (HANA) 中不同行的值?
How to aggregate values from different rows in sql (HANA)?
我有一个 table 的发货定义(如果相关,table 存储在 HANA 数据库中):
CREATE COLUMN TABLE SHIPMENTS (
ShipmentID INT PRIMARY KEY,
Received INT,
Facility NVARCHAR(10),
Item NVARCHAR(20)
);
这里'Received'栏表示每批货物的接收时间点,Facility是货物的接收地点,Item是货物的内容。
我已经用这样的数据填充了它:
INSERT INTO SHIPMENTS VALUES (1, 0, 'Factory', 'Production machine');
INSERT INTO SHIPMENTS VALUES (2, 0, 'Office', 'Printer');
INSERT INTO SHIPMENTS VALUES (3, 0, 'Factory', 'Coffee maker');
INSERT INTO SHIPMENTS VALUES (4, 1, 'Office', 'Coffee maker');
INSERT INTO SHIPMENTS VALUES (5, 1, 'Factory', 'Fax Machine');
INSERT INTO SHIPMENTS VALUES (6, 2, 'Office', 'Computers');
INSERT INTO SHIPMENTS VALUES (7, 2, 'Factory', 'Fridge');
INSERT INTO SHIPMENTS VALUES (8, 2, 'Factory', 'Freezer');
INSERT INTO SHIPMENTS VALUES (9, 2, 'Office', 'Fax Machine');
我想查询数据库以查找在每个时间点之前收到了哪些项目。根据另一个线程的回答,我首先这样做:
SELECT Facility, Received, STRING_AGG (Item, ';') as Items
FROM (
SELECT * FROM SHIPMENTS
ORDER BY Facility, Received
)
GROUP BY Facility, Received
ORDER BY Facility, Received;
这导致
| FACILITY | RECEIVED | ITEMS
---------------------------------------------------------
1 | Factory | 0 | Production Machine;Coffee maker
2 | Factory | 1 | Fax Machine
3 | Factory | 2 | Fridge;Freezer
4 | Office | 0 | Printer
5 | Office | 1 | Coffee maker
6 | Office | 2 | Computers;Fax Machine
不过,我想要这个
| FACILITY | RECEIVED | ITEMS
---------------------------------------------------------
1 | Factory | 0 | Production Machine;Coffee maker
2 | Factory | 1 | Production Machine;Coffee maker;Fax Machine
3 | Factory | 2 | Production Machine;Coffee maker;Fax Machine;Fridge;Freezer
4 | Office | 0 | Printer
5 | Office | 1 | Printer;Coffee maker
6 | Office | 2 | Printer;Coffee maker;Computers;Fax Machine
即,每一行显示当时收到的内容,以及已经收到的所有内容。在 SQL 中有没有好的方法来做到这一点?
您可以尝试在select子句中使用相关查询来生成您想要的csv数据:
SELECT
Facility,
Received,
(SELECT STRING_AGG (s2.Item, ';') FROM SHIPMENTS s2
WHERE s2.Facility = s1.Facility AND s2.Received <= s1.Received
GROUP BY s2.Facility) AS ITEMS
FROM SHIPMENTS s1
GROUP BY
Facility,
Received
ORDER BY
Facility;
也许将 ORDER BY 子句与 String_Agg 函数一起使用可能是个好主意,以确保连接按所需顺序进行
select
distinct Facility, Received,
(
select string_agg(s.Item, ';' order by Received, ShipmentID)
from Shipments s
where
s.Facility = t.Facility and
s.Received <= t.Received
) as Items
from Shipments t
我有一个 table 的发货定义(如果相关,table 存储在 HANA 数据库中):
CREATE COLUMN TABLE SHIPMENTS (
ShipmentID INT PRIMARY KEY,
Received INT,
Facility NVARCHAR(10),
Item NVARCHAR(20)
);
这里'Received'栏表示每批货物的接收时间点,Facility是货物的接收地点,Item是货物的内容。
我已经用这样的数据填充了它:
INSERT INTO SHIPMENTS VALUES (1, 0, 'Factory', 'Production machine');
INSERT INTO SHIPMENTS VALUES (2, 0, 'Office', 'Printer');
INSERT INTO SHIPMENTS VALUES (3, 0, 'Factory', 'Coffee maker');
INSERT INTO SHIPMENTS VALUES (4, 1, 'Office', 'Coffee maker');
INSERT INTO SHIPMENTS VALUES (5, 1, 'Factory', 'Fax Machine');
INSERT INTO SHIPMENTS VALUES (6, 2, 'Office', 'Computers');
INSERT INTO SHIPMENTS VALUES (7, 2, 'Factory', 'Fridge');
INSERT INTO SHIPMENTS VALUES (8, 2, 'Factory', 'Freezer');
INSERT INTO SHIPMENTS VALUES (9, 2, 'Office', 'Fax Machine');
我想查询数据库以查找在每个时间点之前收到了哪些项目。根据另一个线程的回答,我首先这样做:
SELECT Facility, Received, STRING_AGG (Item, ';') as Items
FROM (
SELECT * FROM SHIPMENTS
ORDER BY Facility, Received
)
GROUP BY Facility, Received
ORDER BY Facility, Received;
这导致
| FACILITY | RECEIVED | ITEMS
---------------------------------------------------------
1 | Factory | 0 | Production Machine;Coffee maker
2 | Factory | 1 | Fax Machine
3 | Factory | 2 | Fridge;Freezer
4 | Office | 0 | Printer
5 | Office | 1 | Coffee maker
6 | Office | 2 | Computers;Fax Machine
不过,我想要这个
| FACILITY | RECEIVED | ITEMS
---------------------------------------------------------
1 | Factory | 0 | Production Machine;Coffee maker
2 | Factory | 1 | Production Machine;Coffee maker;Fax Machine
3 | Factory | 2 | Production Machine;Coffee maker;Fax Machine;Fridge;Freezer
4 | Office | 0 | Printer
5 | Office | 1 | Printer;Coffee maker
6 | Office | 2 | Printer;Coffee maker;Computers;Fax Machine
即,每一行显示当时收到的内容,以及已经收到的所有内容。在 SQL 中有没有好的方法来做到这一点?
您可以尝试在select子句中使用相关查询来生成您想要的csv数据:
SELECT
Facility,
Received,
(SELECT STRING_AGG (s2.Item, ';') FROM SHIPMENTS s2
WHERE s2.Facility = s1.Facility AND s2.Received <= s1.Received
GROUP BY s2.Facility) AS ITEMS
FROM SHIPMENTS s1
GROUP BY
Facility,
Received
ORDER BY
Facility;
也许将 ORDER BY 子句与 String_Agg 函数一起使用可能是个好主意,以确保连接按所需顺序进行
select
distinct Facility, Received,
(
select string_agg(s.Item, ';' order by Received, ShipmentID)
from Shipments s
where
s.Facility = t.Facility and
s.Received <= t.Received
) as Items
from Shipments t