如何从一个 table 中获取项目列表以及从 mySql 中的花药中获取所有相关项目的列表？

Question

我要列出所有 order_status 项以及相关订单的总数。我尝试使用 inner join 和 left join，但是 none 对我有用。

select
order_status.order_status_id, order_status.name, sum(order.order_id)
where language_id = 1

http://sqlfiddle.com/#!9/7efcbe

以下是表格：

CREATE TABLE IF NOT EXISTS `order` (
    `order_id` int(11) NOT NULL AUTO_INCREMENT,
    `store_id` int(11) NOT NULL DEFAULT '0',
    `order_status_id` int(11) NOT NULL DEFAULT '0',
    `language_id` int(11) NOT NULL,
    PRIMARY KEY (`order_id`)
) ENGINE=MyISAM AUTO_INCREMENT=0 DEFAULT CHARSET=utf8;

CREATE TABLE IF NOT EXISTS `order_status` (
    `order_status_id` int(11) NOT NULL AUTO_INCREMENT,
    `language_id` int(11) NOT NULL,
    `name` varchar(32) NOT NULL,
    PRIMARY KEY (`order_status_id`,`language_id`)
) ENGINE=MyISAM AUTO_INCREMENT=17 DEFAULT CHARSET=utf8;

Answer 1

这里是查询，也许你在找这个数据--

select os.order_status_id,os.name,count(o.order_id) 
from order_status as os 
left outer join `order` o on os.order_status_id = o.order_status_id
group by os.order_status_id,os.name

Answer 2

尝试：

select os.order_status_id, os.name, sum(o.order_id)
from `order_status` os JOIN `order` o on os.order_status_id=o.order_status_id
AND o.language_id = 1
GROUP BY o.order_status_id;

Answer 3

您可以尝试此解决方案来解决您的问题：

select order_status.order_status_id,order_status.name,count(o.order_id) AS no_of_order
from order_status 
left outer join `order` o on order_status.order_status_id = o.order_status_id
group by order_status.order_status_id,order_status.name

您也可以访问http://sqlfiddle.com/#!9/7efcbe/22

如何从一个 table 中获取项目列表以及从 mySql 中的花药中获取所有相关项目的列表？

How to get a list of items from one table and total of their related items from anther in mySql?

mysql

sqlfiddle