比较 2 个数组值仅推送第一个结果

Question

我有一个数组，我需要比较它的值 - 如果有重复 - 我想将它们存储在数组中，例如：

 obj1 = [{"manager_id":1,"name":"john"},{"manager_id":1,"name":"kile"},
 {"manager_id":2,"name":"kenny"},
 {"manager_id":4,"name":"stan"}]

 obj2 = [{"employees_id":1,"name":"dan"},
 {"employees_id":1,"name":"ben"},{"employees_id":1,"name":"sarah"},
 {"employees_id":2,"name":"kelly"}]

如果 "manger_id" === "employees_id - 那么结果将是：

 // {1:[{"manager_id":1,"name":"john"},{"manager_id":1,"name":"kile"},
    {"employees_id":1,"name":"dan"}, {"employees_id":1,"name":"ben"},
    {"employees_id":1,"name":"sarah"}]};

我试过了：

var obj1 = [{
  "manager_id": 1,
  "name": "john"
}, {
  "manager_id": 1,
  "name": "kile"
}, {
  "manager_id": 2,
  "name": "kenny"
}, {
  "manager_id": 4,
  "name": "stan"
}];

var obj2 = [{
  "employees_id": 1,
  "name": "dan"
}, {
  "employees_id": 1,
  "name": "ben"
}, {
  "employees_id": 1,
  "name": "sarah"
}, {
  "employees_id": 2,
  "name": "kelly"
}];

var res = obj1.concat(obj2).reduce(function(r, o) {

  r[o.manager_id] = r[o.employees_id] || [];
  r[o.manager_id].push(o);


  return r;
}, {});


console.log(res);

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如您所愿，"manager_id" 的结果未添加 - 只有一个 - 当应该有更多

if manager_id === employees_id // 应该在第一个键中输出

{1:[{"manager_id":1,"name":"john"},{"manager_id":1,"name":"kile"},
    {"employees_id":1,"name":"dan"}, {"employees_id":1,"name":"ben"},
    {"employees_id":1,"name":"sarah"}]};

如您所见，有几个常见的 id

Answer 1

r[o.manager_id] = r[o.employees_id] || []; 在此语句中，如果经理没有 employee_id 则正在为该 ID 重置数组。

一种正确的方法是：

var res = obj1.concat(obj2).reduce(function(r, o) {
  var id;
  if(o.hasOwnProperty('manager_id')) {
    id = o['manager_id'];
  }
  else {
    id = o['employees_id'];
  }

  r[id] = r[id] || [];
  r[id].push(o);

  return r;
}, {});

Answer 2

问题出在这一行：

r[o.manager_id] = r[o.employees_id] || [];

你应该记住，你的数组中的一些对象有 manager_id 而其他一些没有，它们有 employees_id 相反，所以你必须首先用这一行评估它:

var itemId = o.manager_id || o.employees_id;

试试这个代码：

var res = obj1.concat(obj2).reduce(function(r, o) {
  var itemId = o.manager_id || o.employees_id;
  r[itemId] = r[itemId] || [];
  r[itemId].push(o);


  return r;
}, {});

比较 2 个数组值仅推送第一个结果

Comparing 2 array values push only first result

javascript

ecmascript-5