文本文件中的字母加扰

Question

我正在准备一个测试数据，其中必须有不同的字母说 அ-20 次 ம-30次，த-40次.....（它们是UTF-8编码支持的泰米尔语字母）这可以使用打印语句

来实现

{print ( ' ம் ' * 30 ) + ( ' த ' * 40  ) + }

但是，我需要将它们打乱，这样它们就不会以任何特定的顺序出现。我有大约 230 多封信，我将打印 20、30、40 次。然后我需要打乱它们并将它们写入输出文件。在这方面的任何帮助都是有帮助的。

Answer 1

只需使用random.choice:

import random
size = 1000
values = [' ம் ', ' த ', ' த ']
print "".join(random.choice(values) for i in xrange(size))

Answer 2

我建议将此问题分为 3 个部分：assemble 你的字母列表，打乱列表，然后将其写入文件。请注意，以下代码中的第一行应位于 python 文件的顶部，以允许您在源代码本身中使用 utf-8 字符。

# -*- coding: utf-8 -*-

import codecs  # To write UTF-8 characters to a file
import random

# Assemble data list    
letters = [u'அ', u'ம', u'த']
data = []  # This list will hold the shuffled data

for current_letter in letters:
    # Choose how many times to repeat the current letter.
    times_repeated = random.choice([20, 30, 40])
    data.extend([current_letter] * times_repeated)

# Now, shuffle the 'data' list
random.shuffle(data)

# Now write the shuffled list to a file as one continuous string
data_string = "".join(data)

with codecs.open("data.txt", "w", "utf-8") as f:
    f.write(data_string)

请注意，如果您知道希望每个字母出现多少次，您可以将该信息放入字典中，而不是从 [20, 30, 40]:

中随机选择

# The key is the letter to repeat, the value is the number of times to repeat it
letters = {u'அ': 20,
           u'ம': 30,
           u'த': 20}

for letter in letters:
    times_repeated = letters[letter]
    # ... rest of the code would look the same ...

Answer 3

您可以通过多种方式解决此问题。最有效的方法是使用 random module.

`random.shuffle`

>>> from random import shuffle
>>> my_string = list('This is a test string.')
>>> shuffle(my_string)
>>> scrambled = ''.join(my_string)
>>> print(scrambled)
.sTtha te s rtisns gii

为此，您必须从字符串的字符创建一个list，因为字符串是immutable.

A new object has to be created if a different value has to be stored.

`random.sample`

>>> from random import sample
>>> my_string = 'This is a test string.'
>>> scrambled = random.sample(my_string, len(my_string))
>>> scrambled = ''.join(scrambled)
>>> print(scrambled)
gr.s i tisstheit Tn sa

您不必为此创建 list；因为，来自 random.sample 文档：

Returns a new list containing elements from the population while leaving the original population unchanged.

The `sorted` built-in with `random.random`

>>> from random import random
>>> my_string = 'This is a test string.'
>>> scrambled = sorted(my_string, key=lambda i: random())
>>> scrambled = ''.join(scrambled)
>>> print(scrambled)
ngi rts ithsT.staie s

您也不需要 list。来自 sorted 文档：

Return a new sorted list from the items in iterable.

因为字符串在 Python 中被视为 iterable（见下文），所以可以在其上使用 sorted。

可迭代定义为

An object capable of returning its members one at a time.

Answer 4

感谢帮助我编写代码的朋友@AswinMurugesh。

以下代码成功了。

import codecs
import tamil
from random import shuffle

inp_file = codecs.open("/home/sibi/Desktop/scramble.txt",encoding="utf-8")
inp_text = inp_file.read().rstrip()

tamil_letters = tamil.utf8.get_letters(inp_text)
shuffle(tamil_letters)
tamil_letters = "".join(tamil_letters).encode("utf-8")
print tamil_letters

out_file = open('outputscrambled.txt','w')
out_file.write(tamil_letters)

文本文件中的字母加扰

Scrambling of letters within a text file

python

string

scramble

random.shuffle

random.sample

The sorted built-in with random.random

`random.shuffle`

`random.sample`

The `sorted` built-in with `random.random`