Rspec 中的间谍问题
Issue with spies in Rspec
无法找出原因:
it "shifts/unshifts without O(n) copying" do
arr = RingBuffer.new
allow(arr.send(:store)).to receive(:[]=).and_call_original
8.times do |i|
arr.unshift(i)
end
# Should involve 8 sets to unshift, no more.
expect(arr.send(:store)).to have_received(:[]=).exactly(8).times
end
结果:
"Failure/Error: expect(arr.store).to have_received(:[]=).exactly(8).times
# 预期已收到 []=,但该对象不是间谍或方法尚未存根。"
不确定您的代码在做什么,但我怀疑每次调用 arr.send(:store)
returns 不同的对象。尝试这样修改:
it "shifts/unshifts without O(n) copying" do
arr = RingBuffer.new
store = arr.send(:store)
allow(store).to receive(:[]=).and_call_original
8.times do |i|
arr.unshift(i)
end
# Should involve 8 sets to unshift, no more.
expect(store).to have_received(:[]=).exactly(8).times
end
无法找出原因:
it "shifts/unshifts without O(n) copying" do
arr = RingBuffer.new
allow(arr.send(:store)).to receive(:[]=).and_call_original
8.times do |i|
arr.unshift(i)
end
# Should involve 8 sets to unshift, no more.
expect(arr.send(:store)).to have_received(:[]=).exactly(8).times
end
结果:
"Failure/Error: expect(arr.store).to have_received(:[]=).exactly(8).times # 预期已收到 []=,但该对象不是间谍或方法尚未存根。"
不确定您的代码在做什么,但我怀疑每次调用 arr.send(:store)
returns 不同的对象。尝试这样修改:
it "shifts/unshifts without O(n) copying" do
arr = RingBuffer.new
store = arr.send(:store)
allow(store).to receive(:[]=).and_call_original
8.times do |i|
arr.unshift(i)
end
# Should involve 8 sets to unshift, no more.
expect(store).to have_received(:[]=).exactly(8).times
end