ORM

Question

我在 ORM 的 Node.js 后端使用 PostgreSQL 和 objection.js。我只有两个具有一对一关系的简单 table。我无法将新记录插入 table.

我有一个包含员工和薪水的简单数据库模式 table:

CREATE TABLE employee (
    employee_id SERIAL PRIMARY KEY,
    employee_name VARCHAR
);

INSERT INTO employee (employee_name) VALUES ('james');

CREATE TABLE salary (
  salary_id SERIAL PRIMARY KEY,
  employee_id SERIAL UNIQUE,
  FOREIGN KEY (employee_id) REFERENCES employee (employee_id),
  amount integer
);

如果我想通过objection.js创建新的工资记录：

Salary.query()
          .insert({ employee_id: 1, amount: 10 })
          .then((data) => {
            console.log(data);
          })
          .catch((err) => {
            throw err;
          });

我收到错误：

Unhandled rejection error: column "id" does not exist
at Connection.parseE (./node_modules/pg/lib/connection.js:546:11)
at Connection.parseMessage (./node_modules/pg/lib/connection.js:371:19)
at TLSSocket.<anonymous> (./node_modules/pg/lib/connection.js:114:22)
at emitOne (events.js:115:13)
at TLSSocket.emit (events.js:210:7)
at addChunk (_stream_readable.js:252:12)
at readableAddChunk (_stream_readable.js:239:11)
at TLSSocket.Readable.push (_stream_readable.js:197:10)
at TLSWrap.onread (net.js:589:20)

testSalary.js

const { Model, snakeCaseMappers } = require('objection');

class Salary extends Model {
  static get tableName() {
    return 'salary';
  }

  static get columnNameMappers() {
    return snakeCaseMappers();
  }

  static get jsonSchema() {
    return {
      type: 'object',

      properties: {
        salary_id: { type: 'integer' },
        employee_id: { type: 'integer' },
        amount: { type: 'integer' },
      },
    };
  }

  static get relationMappings() {
    return {
      employee: {
        relation: Model.BelongsToOneRelation,
        modelClass: `${__dirname}/testEmployee`,
        join: {
          from: 'salary.employee_id',
          to: 'employee.employee_id',
        },
      },
    };
  }
}

module.exports = Salary;

testEmployee.js

const { Model, snakeCaseMappers } = require('objection');

class Employee extends Model {
  static get tableName() {
    return 'employee';
  }

  static get columnNameMappers() {
    return snakeCaseMappers();
  }

  static get jsonSchema() {
    return {
      type: 'object',

      properties: {
        employee_id: { type: 'integer' },
        employee_name: { type: 'string' },
      },
    };
  }

  static get relationMappings() {
    return {
      salary: {
        relation: Model.HasManyRelation,
        modelClass: `${__dirname}/testSalary`,
        join: {
          from: 'employee.employee_id',
          to: 'salary.employee_id',
        },
      },
    };
  }
}

module.exports = Employee;

Answer 1

我的猜测是这与引擎盖下对 Knex 的依赖有关。在 the docs 中，有一个代码片段建议通过 Knex 迁移创建表。也许这样做会解决您的问题，因为 Knex 可能会创建一个反对意见期望存在的 id 列。

Answer 2

需要通过在 Model 类.

上定义 idColumn 来告知反对意见 id 列是什么

class Salary extends Model {
  static get tableName() {
    return 'salary';
  }

  static get idColumn() {
    return 'salary_id';
  }
  // etc
}

使用迁移来创建表将通过创建表并将其 id 列命名为 id 来完成这项工作，但是如果您定义 idColumn，则可以在没有迁移的情况下使用异议。 =15=]

ORM - rejection error: column "id" does not exist

ORM - rejection error: column "id" does not exist

node.js

postgresql

node-postgres

objection.js