获取 Swift 点的像素颜色
Get Color Of Pixel At Point In Swift
我在此处找到了一个 Objective-C 代码示例,它获取某个点的像素颜色:
How to get the pixel color on touch?
我需要帮助的特定代码部分是使用 CGColorSpaceCreateDeviceRGB 创建上下文的位置:
---这是Objective-C代码
unsigned char pixel[4] = {0};
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
CGContextRef context = CGBitmapContextCreate(pixel,
1, 1, 8, 4, colorSpace, (CGBitmapInfo)kCGImageAlphaPremultipliedLast);
CGContextTranslateCTM(context, -point.x, -point.y);
我最好的尝试如下(我没有返回任何东西,但我试图首先正确获取上下文):
---这是我在 Swift 转换中的最佳尝试
func getPixelColorAtPoint()
{
let pixel = UnsafeMutablePointer<CUnsignedChar>.alloc(1)
var colorSpace:CGColorSpaceRef = CGColorSpaceCreateDeviceRGB()
let context = CGBitmapContextCreate(pixel, width: 1, height: 1, bitsPerComponent: 8, bytesPerRow: 4, space: nil, bitmapInfo: CGImageAlphaInfo.PremultipliedLast)
}
但是这给了我一个错误
Cannot convert the expression's type '(UnsafeMutablePointer<CUnsignedChar>, width: IntegerLiteralConvertible, height: IntegerLiteralConvertible, bitsPerComponent: IntegerLiteralConvertible, bytesPerRow: IntegerLiteralConvertible, space: NilLiteralConvertible, bitmapInfo: CGImageAlphaInfo)' to type 'IntegerLiteralConvertible'
如果您能告诉我如何调整上面的代码以正确输入上下文函数参数,我将不胜感激!
有两个不同的问题:
CGBitmapContextCreate()
是一个 函数 ,不是 方法 ,因此不
默认使用外部参数名称。
CGImageAlphaInfo.PremultipliedLast
不能作为 bitmapInfo:
参数传递,
比较 Swift OpenGL unresolved identifier kCGImageAlphaPremultipliedLast.
所以这应该编译:
let pixel = UnsafeMutablePointer<CUnsignedChar>.alloc(4)
var colorSpace = CGColorSpaceCreateDeviceRGB()
let bitmapInfo = CGBitmapInfo(CGImageAlphaInfo.PremultipliedLast.rawValue)
let context = CGBitmapContextCreate(pixel, 1, 1, 8, 4, colorSpace, bitmapInfo)
// ...
pixel.dealloc(4)
请注意,您应该为 4 个字节分配 space,而不是 1 个。
或者:
var pixel : [UInt8] = [0, 0, 0, 0]
var colorSpace = CGColorSpaceCreateDeviceRGB()
let bitmapInfo = CGBitmapInfo(CGImageAlphaInfo.PremultipliedLast.rawValue)
let context = CGBitmapContextCreate(UnsafeMutablePointer(pixel), 1, 1, 8, 4, colorSpace, bitmapInfo)
我在此处找到了一个 Objective-C 代码示例,它获取某个点的像素颜色: How to get the pixel color on touch?
我需要帮助的特定代码部分是使用 CGColorSpaceCreateDeviceRGB 创建上下文的位置:
---这是Objective-C代码
unsigned char pixel[4] = {0};
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
CGContextRef context = CGBitmapContextCreate(pixel,
1, 1, 8, 4, colorSpace, (CGBitmapInfo)kCGImageAlphaPremultipliedLast);
CGContextTranslateCTM(context, -point.x, -point.y);
我最好的尝试如下(我没有返回任何东西,但我试图首先正确获取上下文):
---这是我在 Swift 转换中的最佳尝试
func getPixelColorAtPoint()
{
let pixel = UnsafeMutablePointer<CUnsignedChar>.alloc(1)
var colorSpace:CGColorSpaceRef = CGColorSpaceCreateDeviceRGB()
let context = CGBitmapContextCreate(pixel, width: 1, height: 1, bitsPerComponent: 8, bytesPerRow: 4, space: nil, bitmapInfo: CGImageAlphaInfo.PremultipliedLast)
}
但是这给了我一个错误
Cannot convert the expression's type '(UnsafeMutablePointer<CUnsignedChar>, width: IntegerLiteralConvertible, height: IntegerLiteralConvertible, bitsPerComponent: IntegerLiteralConvertible, bytesPerRow: IntegerLiteralConvertible, space: NilLiteralConvertible, bitmapInfo: CGImageAlphaInfo)' to type 'IntegerLiteralConvertible'
如果您能告诉我如何调整上面的代码以正确输入上下文函数参数,我将不胜感激!
有两个不同的问题:
CGBitmapContextCreate()
是一个 函数 ,不是 方法 ,因此不 默认使用外部参数名称。CGImageAlphaInfo.PremultipliedLast
不能作为bitmapInfo:
参数传递, 比较 Swift OpenGL unresolved identifier kCGImageAlphaPremultipliedLast.
所以这应该编译:
let pixel = UnsafeMutablePointer<CUnsignedChar>.alloc(4)
var colorSpace = CGColorSpaceCreateDeviceRGB()
let bitmapInfo = CGBitmapInfo(CGImageAlphaInfo.PremultipliedLast.rawValue)
let context = CGBitmapContextCreate(pixel, 1, 1, 8, 4, colorSpace, bitmapInfo)
// ...
pixel.dealloc(4)
请注意,您应该为 4 个字节分配 space,而不是 1 个。
或者:
var pixel : [UInt8] = [0, 0, 0, 0]
var colorSpace = CGColorSpaceCreateDeviceRGB()
let bitmapInfo = CGBitmapInfo(CGImageAlphaInfo.PremultipliedLast.rawValue)
let context = CGBitmapContextCreate(UnsafeMutablePointer(pixel), 1, 1, 8, 4, colorSpace, bitmapInfo)