从 google 中的 IOS 地图位置 api 中提取 Require 信息
Extracting Require information from google map place api in IOS
我正在开发 GPS 应用程序，我需要根据 place.I 的经度和纬度确定位置我能够确定经度和纬度以及位置，但我得到的结果是 google 地图 api 以 json 格式调用，其中有大量数据以及城市名称。
我是这样做的。（我用的是模拟器，所以我已经通过了固定的经纬度）
NSString *urlString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297, 76.444017];
NSError* error;
NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];
locationString = [locationString stringByReplacingOccurrencesOfString:@"\"" withString:@""];
NSLog(@"%@",locationString );
我得到的输出字符串是
015-04-16 10:38:45.056 demolocationapp[690:12005] {
results : [
{
address_components : [
{
long_name : Rauni Kalan Link Road,
short_name : Rauni Kalan Link Rd,
types : [ route ]
},
{
**long_name : Rauni Kalan,
short_name : Rauni Kalan,
types : [ locality, political]**
},
{
long_name : Rupnagar,
short_name : Rupnagar,
types : [ administrative_area_level_2, political ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
},
{
long_name : 140102,
short_name : 140102,
types : [ postal_code ]
}
],
formatted_address : Rauni Kalan Link Road, Rauni Kalan, Punjab 140102, India,
geometry : {
bounds : {
northeast : {
lat : 30.8209903,
lng : 76.4550081
},
southwest : {
lat : 30.8178417,
lng : 76.44540219999999
}
},
location : {
lat : 30.8186057,
lng : 76.4507395
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.8209903,
lng : 76.4550081
},
southwest : {
lat : 30.8178417,
lng : 76.44540219999999
}
}
},
place_id : ChIJc8IoHwICEDkR38Ie5TOeGu0,
types : [ route ]
},
{
address_components : [
{
long_name : Rauni Kalan,
short_name : Rauni Kalan,
types : [ locality, political ]
},
{
long_name : Rupnagar,
short_name : Rupnagar,
types : [ administrative_area_level_2, political ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
},
{
long_name : 140102,
short_name : 140102,
types : [ postal_code ]
}
],
formatted_address : Rauni Kalan, Punjab 140102, India,
geometry : {
bounds : {
northeast : {
lat : 30.8219531,
lng : 76.4462614
},
southwest : {
lat : 30.81705139999999,
lng : 76.4414979
}
},
location : {
lat : 30.8192965,
lng : 76.44401660000001
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.8219531,
lng : 76.4462614
},
southwest : {
lat : 30.81705139999999,
lng : 76.4414979
}
}
},
place_id : ChIJ_f1PWh0CEDkRKlzFwhc62zo,
types : [ locality, political ]
},
{
address_components : [
{
long_name : 140102,
short_name : 140102,
types : [ postal_code ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : Punjab 140102, India,
geometry : {
bounds : {
northeast : {
lat : 30.869706,
lng : 76.47508049999999
},
southwest : {
lat : 30.7970006,
lng : 76.3335855
}
},
location : {
lat : 30.8288892,
lng : 76.4215988
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.869706,
lng : 76.47508049999999
},
southwest : {
lat : 30.7970006,
lng : 76.3335855
}
}
},
place_id : ChIJHX2_rA0BEDkR_QslHcc_M0g,
types : [ postal_code ]
},
{
address_components : [
{
long_name : Fatehgarh Sahib,
short_name : Fatehgarh Sahib,
types : [ administrative_area_level_2, political ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : Fatehgarh Sahib, Punjab, India,
geometry : {
bounds : {
northeast : {
lat : 30.8779699,
lng : 76.63427999999999
},
southwest : {
lat : 30.4275501,
lng : 76.0761799
}
},
location : {
lat : 30.6810924,
lng : 76.4100267
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.8779699,
lng : 76.63427999999999
},
southwest : {
lat : 30.4275501,
lng : 76.0761799
}
}
},
place_id : ChIJqf6CHWocEDkR4EljDGd5be8,
types : [ administrative_area_level_2, political ]
},
{
address_components : [
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : Punjab, India,
geometry : {
bounds : {
northeast : {
lat : 32.4981352,
lng : 76.92175809999999
},
southwest : {
lat : 29.537147,
lng : 73.8708879
}
},
location : {
lat : 31.1471305,
lng : 75.34121789999999
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 32.4981352,
lng : 76.92175809999999
},
southwest : {
lat : 29.537147,
lng : 73.8708879
}
}
},
place_id : ChIJVXOeVqpkGTkRYYijAzEmvY8,
types : [ administrative_area_level_1, political ]
},
{
address_components : [
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : India,
geometry : {
bounds : {
northeast : {
lat : 35.5087008,
lng : 97.395561
},
southwest : {
lat : 6.7535159,
lng : 68.162386
}
},
location : {
lat : 20.593684,
lng : 78.96288
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 35.5087008,
lng : 97.395561
},
southwest : {
lat : 6.7535159,
lng : 68.16288519999999
}
}
},
place_id : ChIJkbeSa_BfYzARphNChaFPjNc,
types : [ country, political ]
}
],
status : OK
}
我已将我的必填数据放在 type 是 locality,political 的 **Required Text **
我怎样才能得到那个
用过这个方法
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat: @"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297, 76.444017]];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
if (!error)
{
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSArray *arr=[[json valueForKeyPath:@"results.address_components"] objectAtIndex:0];
for (NSDictionary *dictAddress in arr)
{
if ([[dictAddress objectForKey:@"types"] count] > 0)
{
if([[[dictAddress objectForKey:@"types"] objectAtIndex:0] isEqualToString:@"locality"])
{
return [dictAddress objectForKey:@"long_name"];
}
else if([[[dictAddress objectForKey:@"types"] objectAtIndex:0] isEqualToString:@"political"])
{
return [dictAddress objectForKey:@"long_name"];
}
}
else
{
return @"";
}
}
return @"";
}
}
}];
使用此方法，您将找到以 "locality" 或 "political" 开头的区域名称。
但我已经获取了 api 响应的第一个对象，但是如果您需要比这更多的 rathar ，则放置循环以获取调用的 json 的对象。
希望对您有所帮助。
您需要将 JSON 对象的字符串转换为 NSDictionary，然后使用 key/value 访问器获取每个字段。
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat: @"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297, 76.444017]];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
if (!error)
{
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSArray *results = [json valueForKey:@"results"];
for (NSDictionary *result in results)
{
NSLog(@"%@", [result valueForKey:@"formatted_address"]);
NSLog(@"%@", [result valueForKey:@"place_id"]);
// Etc...
}
}
}];
首先，我会使用 NSURLSession 和块来进行网络调用。块的美妙之处在于，如果我的网络连接很差，我的块只会在调用 returns.
之后执行
然后您需要将 JSON 转换为您可以使用的基础对象。
NSString *urlString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297,76.444017];
NSURL *url = [NSURL URLWithString:urlString];
//Next we need a NSURLSession instance
NSURLSession *session = [NSURLSession sharedSession];
//All tasks (there are three, see documentation) are created from an NSURLSession instance
//We want a DataTask
NSURLSessionDataTask *dataTask = [session dataTaskWithURL:url completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
//This "block" (of code) will be executed when the call is complete
//Serialize the JSON to Foundation objects
NSDictionary *geocodeDictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
//Parse through the JSON to get to where we want, address_components array
NSArray *resultsArray = geocodeDictionary[@"results"];
NSDictionary *resultsDictionary = resultsArray[0];
NSArray *addressComponents = resultsDictionary[@"address_components"];
//Declare variables to hold desired results
NSString *longName;
NSString *shortName;
//The address_components array contains many dictionaries,
//we loop through each dictionary and check the types array
for (NSDictionary *addressComponentDictionary in addressComponents) {
NSArray *typesArray = addressComponentDictionary[@"types"];
if ( [typesArray[0] isEqualToString:@"locality"]
&& [typesArray[1] isEqualToString:@"political"]) {
//the type IS locality and political
longName = addressComponentDictionary[@"long_name"];
shortName = addressComponentDictionary[@"short_name"];
}
}
//Test log to see we are correct
NSLog(@"%@", longName);
NSLog(@"%@", shortName);
}];
[dataTask resume];
我正在开发 GPS 应用程序，我需要根据 place.I 的经度和纬度确定位置我能够确定经度和纬度以及位置，但我得到的结果是 google 地图 api 以 json 格式调用，其中有大量数据以及城市名称。
我是这样做的。（我用的是模拟器，所以我已经通过了固定的经纬度）
NSString *urlString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297, 76.444017];
NSError* error;
NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];
locationString = [locationString stringByReplacingOccurrencesOfString:@"\"" withString:@""];
NSLog(@"%@",locationString );
我得到的输出字符串是
015-04-16 10:38:45.056 demolocationapp[690:12005] {
results : [
{
address_components : [
{
long_name : Rauni Kalan Link Road,
short_name : Rauni Kalan Link Rd,
types : [ route ]
},
{
**long_name : Rauni Kalan,
short_name : Rauni Kalan,
types : [ locality, political]**
},
{
long_name : Rupnagar,
short_name : Rupnagar,
types : [ administrative_area_level_2, political ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
},
{
long_name : 140102,
short_name : 140102,
types : [ postal_code ]
}
],
formatted_address : Rauni Kalan Link Road, Rauni Kalan, Punjab 140102, India,
geometry : {
bounds : {
northeast : {
lat : 30.8209903,
lng : 76.4550081
},
southwest : {
lat : 30.8178417,
lng : 76.44540219999999
}
},
location : {
lat : 30.8186057,
lng : 76.4507395
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.8209903,
lng : 76.4550081
},
southwest : {
lat : 30.8178417,
lng : 76.44540219999999
}
}
},
place_id : ChIJc8IoHwICEDkR38Ie5TOeGu0,
types : [ route ]
},
{
address_components : [
{
long_name : Rauni Kalan,
short_name : Rauni Kalan,
types : [ locality, political ]
},
{
long_name : Rupnagar,
short_name : Rupnagar,
types : [ administrative_area_level_2, political ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
},
{
long_name : 140102,
short_name : 140102,
types : [ postal_code ]
}
],
formatted_address : Rauni Kalan, Punjab 140102, India,
geometry : {
bounds : {
northeast : {
lat : 30.8219531,
lng : 76.4462614
},
southwest : {
lat : 30.81705139999999,
lng : 76.4414979
}
},
location : {
lat : 30.8192965,
lng : 76.44401660000001
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.8219531,
lng : 76.4462614
},
southwest : {
lat : 30.81705139999999,
lng : 76.4414979
}
}
},
place_id : ChIJ_f1PWh0CEDkRKlzFwhc62zo,
types : [ locality, political ]
},
{
address_components : [
{
long_name : 140102,
short_name : 140102,
types : [ postal_code ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : Punjab 140102, India,
geometry : {
bounds : {
northeast : {
lat : 30.869706,
lng : 76.47508049999999
},
southwest : {
lat : 30.7970006,
lng : 76.3335855
}
},
location : {
lat : 30.8288892,
lng : 76.4215988
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.869706,
lng : 76.47508049999999
},
southwest : {
lat : 30.7970006,
lng : 76.3335855
}
}
},
place_id : ChIJHX2_rA0BEDkR_QslHcc_M0g,
types : [ postal_code ]
},
{
address_components : [
{
long_name : Fatehgarh Sahib,
short_name : Fatehgarh Sahib,
types : [ administrative_area_level_2, political ]
},
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : Fatehgarh Sahib, Punjab, India,
geometry : {
bounds : {
northeast : {
lat : 30.8779699,
lng : 76.63427999999999
},
southwest : {
lat : 30.4275501,
lng : 76.0761799
}
},
location : {
lat : 30.6810924,
lng : 76.4100267
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 30.8779699,
lng : 76.63427999999999
},
southwest : {
lat : 30.4275501,
lng : 76.0761799
}
}
},
place_id : ChIJqf6CHWocEDkR4EljDGd5be8,
types : [ administrative_area_level_2, political ]
},
{
address_components : [
{
long_name : Punjab,
short_name : PB,
types : [ administrative_area_level_1, political ]
},
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : Punjab, India,
geometry : {
bounds : {
northeast : {
lat : 32.4981352,
lng : 76.92175809999999
},
southwest : {
lat : 29.537147,
lng : 73.8708879
}
},
location : {
lat : 31.1471305,
lng : 75.34121789999999
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 32.4981352,
lng : 76.92175809999999
},
southwest : {
lat : 29.537147,
lng : 73.8708879
}
}
},
place_id : ChIJVXOeVqpkGTkRYYijAzEmvY8,
types : [ administrative_area_level_1, political ]
},
{
address_components : [
{
long_name : India,
short_name : IN,
types : [ country, political ]
}
],
formatted_address : India,
geometry : {
bounds : {
northeast : {
lat : 35.5087008,
lng : 97.395561
},
southwest : {
lat : 6.7535159,
lng : 68.162386
}
},
location : {
lat : 20.593684,
lng : 78.96288
},
location_type : APPROXIMATE,
viewport : {
northeast : {
lat : 35.5087008,
lng : 97.395561
},
southwest : {
lat : 6.7535159,
lng : 68.16288519999999
}
}
},
place_id : ChIJkbeSa_BfYzARphNChaFPjNc,
types : [ country, political ]
}
],
status : OK
}
我已将我的必填数据放在 type 是 locality,political 的 **Required Text **
我怎样才能得到那个
用过这个方法
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat: @"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297, 76.444017]];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
if (!error)
{
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSArray *arr=[[json valueForKeyPath:@"results.address_components"] objectAtIndex:0];
for (NSDictionary *dictAddress in arr)
{
if ([[dictAddress objectForKey:@"types"] count] > 0)
{
if([[[dictAddress objectForKey:@"types"] objectAtIndex:0] isEqualToString:@"locality"])
{
return [dictAddress objectForKey:@"long_name"];
}
else if([[[dictAddress objectForKey:@"types"] objectAtIndex:0] isEqualToString:@"political"])
{
return [dictAddress objectForKey:@"long_name"];
}
}
else
{
return @"";
}
}
return @"";
}
}
}];
使用此方法，您将找到以 "locality" 或 "political" 开头的区域名称。
但我已经获取了 api 响应的第一个对象，但是如果您需要比这更多的 rathar ，则放置循环以获取调用的 json 的对象。
希望对您有所帮助。
您需要将 JSON 对象的字符串转换为 NSDictionary，然后使用 key/value 访问器获取每个字段。
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat: @"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297, 76.444017]];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[NSURLConnection sendAsynchronousRequest:request queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error) {
if (!error)
{
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSArray *results = [json valueForKey:@"results"];
for (NSDictionary *result in results)
{
NSLog(@"%@", [result valueForKey:@"formatted_address"]);
NSLog(@"%@", [result valueForKey:@"place_id"]);
// Etc...
}
}
}];
首先，我会使用 NSURLSession 和块来进行网络调用。块的美妙之处在于，如果我的网络连接很差，我的块只会在调用 returns.
之后执行然后您需要将 JSON 转换为您可以使用的基础对象。
NSString *urlString = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",30.819297,76.444017];
NSURL *url = [NSURL URLWithString:urlString];
//Next we need a NSURLSession instance
NSURLSession *session = [NSURLSession sharedSession];
//All tasks (there are three, see documentation) are created from an NSURLSession instance
//We want a DataTask
NSURLSessionDataTask *dataTask = [session dataTaskWithURL:url completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
//This "block" (of code) will be executed when the call is complete
//Serialize the JSON to Foundation objects
NSDictionary *geocodeDictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
//Parse through the JSON to get to where we want, address_components array
NSArray *resultsArray = geocodeDictionary[@"results"];
NSDictionary *resultsDictionary = resultsArray[0];
NSArray *addressComponents = resultsDictionary[@"address_components"];
//Declare variables to hold desired results
NSString *longName;
NSString *shortName;
//The address_components array contains many dictionaries,
//we loop through each dictionary and check the types array
for (NSDictionary *addressComponentDictionary in addressComponents) {
NSArray *typesArray = addressComponentDictionary[@"types"];
if ( [typesArray[0] isEqualToString:@"locality"]
&& [typesArray[1] isEqualToString:@"political"]) {
//the type IS locality and political
longName = addressComponentDictionary[@"long_name"];
shortName = addressComponentDictionary[@"short_name"];
}
}
//Test log to see we are correct
NSLog(@"%@", longName);
NSLog(@"%@", shortName);
}];
[dataTask resume];