我如何 select 唯一和重复的行排除不同的值

Question

如何在 Oracle 中按预期获取此 table。我试着像下面 select 那样做，但它没有给我正确的结果。我期望的是只获取唯一的，如果这些是不同值的记录则排除。对不起，如果之前问过，但我找不到。

SELECT * 
FROM ...
WHERE number IN ( SELECT name
                  FROM (SELECT *
                        FROM table
                        WHERE number IN ('Mel','Jose','Kim')
                  ) ds
                  GROUP BY number
                  HAVING COUNT (*) = 1)

当前结果：

 number name
   aaa   Mel
   asd   Jose
   fsa   Jose
   xdf   Jose
   zzz   Kim
   zzz   Kim

预期结果：

aaa Mel
zzz Kim

Answer 1

您可以通过 nested sql 和 the inner part 消除关于 id 和 name 的重复项，而在 the outer part 中消除重复项仅name 如以下语句：

SELECT MAX(id),name 
FROM (SELECT id,name FROM mytable GROUP BY id, name)  
GROUP BY name 
HAVING COUNT(1) = 1
ORDER BY MAX(id);

输出：

ID       NAME
-----    ------
100      Mel
101      Kim

D e m o 1

exactly the same sql works for your second case :

D e m o 2

Answer 2

你很接近 - 我认为你只是在你的 having 子句中遗漏了 distinct。

例如：

WITH your_table AS (SELECT 100 nmbr, 'Mel' NAME FROM dual UNION ALL
                    SELECT 112 nmbr, 'Jose' NAME FROM dual UNION ALL
                    SELECT 212 nmbr, 'Jose' NAME FROM dual UNION ALL
                    SELECT 313 nmbr, 'Jose' NAME FROM dual UNION ALL
                    SELECT 101 nmbr, 'Kim' NAME FROM dual UNION ALL
                    SELECT 101 nmbr, 'Kim' NAME FROM dual)
-- end of mimicking data in your table
-- you already have this table, so you would just need the below sql:
SELECT min(nmbr) nmbr,
       NAME
FROM   your_table
GROUP BY NAME
HAVING COUNT(DISTINCT nmbr) = 1;

      NMBR NAME
---------- ----
       101 Kim
       100 Mel

只是为了证明 nmbr 列是 NUMBER 还是 VARCHAR2 数据类型并不重要：

WITH your_table AS (SELECT 'aaa' nmbr, 'Mel' NAME FROM dual UNION ALL
                    SELECT 'asd' nmbr, 'Jose' NAME FROM dual UNION ALL
                    SELECT 'fsa' nmbr, 'Jose' NAME FROM dual UNION ALL
                    SELECT 'xfd' nmbr, 'Jose' NAME FROM dual UNION ALL
                    SELECT 'zzz' nmbr, 'Kim' NAME FROM dual UNION ALL
                    SELECT 'zzz' nmbr, 'Kim' NAME FROM dual)
-- end of mimicking data in your table
-- you already have this table, so you would just need the below sql:
SELECT min(nmbr) nmbr,
       NAME
FROM   your_table
GROUP BY NAME
HAVING COUNT(DISTINCT nmbr) = 1;

NMBR NAME
---- ----
zzz  Kim
aaa  Mel

我如何 select 唯一和重复的行排除不同的值

How can I select unique and duplicated rows exlude with different values

sql

oracle

group-by

aggregate-functions

having