Coucbbase 中的复杂 N1QL 查询

Complex N1QL query in Coucbbase

我在名为 'entities' 的同一存储桶中的 couchbase 中有以下两种类型的文档:

{
  "documentType": "person",
  "id": "4f3567cd-782d-4456-aabd-ff5faf071476",
  "personal": {
    "gender": "Male",
    "dob": "1984-05-22",
    "firstName": "Peter",
    "lastName": "Smith",
    "idNumber": "4915040000111"
  }
}

和:

{
    "id": "09690237-9ef5-4381-93dc-7312f7417f82",
    "documentType": "link",
    "entities": [
        {
            "id": "000151ef-f4b9-4cd4-bf3b-d5b07d79ed20",
            "type": "parent",
        },
        {
            "id": "000151ef-f4b9-4cd4-bf3b-d5b07d79ed21",
            "type": "child"
        }

    ]
}

人物文档描述了一个人,link table 定义了人与人之间的 link。一个 parent 可以有多个 children,而一个 parent 将有一个 link 文档,他有每个 child。

问题:给定一个parent id,return那个parent的每个child人的所有个人信息,例如

[
    {
        "id": "000151ef-f4b9-4cd4-bf3b-d5b07d79ed21",
        "personal": {
            "gender": "Male",
            "dob": "2004-05-22",
            "firstName": "Chris",
            "lastName": "Smith",
            "idNumber": "0415050000111"
        }
    },
    {
        ...
    }
]

到目前为止:我能够使用以下方法获得所有 children ID 的列表:

select array_flatten(array_agg(array entity.id for entity in entities.entities when entity.type = 'parent' end), 3) as entity
from entities
where entities.docuementType = 'link'
      and any entity within entities satisfies entity.id = '01f6a9eb-0d7e-4495-a90f-f96a38aef621'
                                               and entity.type='parent' end

但是,couchbase 似乎无法在 sub-queries 上执行连接。有没有一种方法可以使用 N1QL 来完成?目前我唯一的解决方案是获取 ID 列表,然后 运行 另一个查询来获取 children.

SELECT p
FROM entities AS l 
JOIN entities AS p 
ON KEYS ARRAY e.id FOR e IN l.entities WHEN e.type = "child" END
WHERE l.docuementType = 'link'
      AND ANY entity IN l.entities 
              SATISFIES entity.id = '01f6a9eb-0d7e-4495-a90f-f96a38aef621'
                       AND entity.type='parent' END