Sql Server 2016 中 json 数据的 Where 子句

Where clause on json data in Sql Server 2016

我的 table 中有一个 nvarchar(1000) 字段,我正在该列中存储 JSON 数据。

例如:

 CONTENT_RULE_ID    CONTENT_RULE
 1                  {"EntityType":"Inquiry", "Values":[1,2]}
 2                  {"EntityType":"Inquiry", "Values":[1,3]}
 3                  {"EntityType":"Inquiry", "Values":[2,4]}
 4                  {"EntityType":"Inquiry", "Values":[5,6,1]}
 6                  {"EntityType":"Inquiry", "Values":[8,1]}
 8                  {"EntityType":"Inquiry", "Values":[10,12,11]}

从这个我怎样才能得到所有 CONTENT_RULE_ID 在 sql server

中使用 JSON_QUERY 查询 ID 1

@Harisyam,你能试试下面的查询吗

declare @val int = 1

;with cte as (
    select *
    from CONTENT_RULES
    cross apply openjson (CONTENT_RULE, '$')
), list as (
    select 
    CONTENT_RULE_ID, replace(replace([value],'[',''),']','') as [value]
    from cte 
    where CONTENT_RULE_ID in (
    select CONTENT_RULE_ID
    from cte 
    where [key] = 'EntityType' and [value] = 'Inquiry'
    ) 
    and [key] = 'Values'
)
select 
CONTENT_RULE_ID, s.value
from list
cross apply string_split([value],',') s
where s.value = @val

我用SQLstring_split function一个一个获取查询值

输出是

第二个查询可以在一个之后

select
    CONTENT_RULE_ID
from CONTENT_RULES
cross apply openjson (CONTENT_RULE, '$')
where replace(replace(value,'[',','),']',',') like '%,1,%'

也许需要 OpenJSON 支持的最完整的 SQL 查询如下

select
    content_rule_id,
    [value]
from Content as c
cross apply openjson(c.CONTENT_RULE, '$') with (
    EntityType nvarchar(100),
    [Values] nvarchar(max) as json
) as e
cross apply openjson([Values], '$') as v

sql服务器2016可以开启JSON.

试试这个:

SELECT c.content_rule_ID, y.[key], y.[value]
  FROM content_rules AS c
  CROSS APPLY OPENJSON(JSON_QUERY(content_rule, '$.content_rule')) AS x
  CROSS APPLY OPENJSON(x.[Values], '$') AS y
  where y.[value] = 1
    and x.[EntityType] = 'Inquiry';
SELECT c.*
FROM CONTENT_RULES AS c
CROSS APPLY OPENJSON(JSON_QUERY(content_rule, '$')) AS x 
CROSS APPLY OPENJSON(x.[Value], '$') AS y
where x.[key]='Values' and y.[value]=1

我的情况类似,但我的不是整数数组,而是复杂类型的数组。这是我的代码基于 David Browne's solution

SELECT *
FROM TableName AS T
WHERE EXISTS
(
    SELECT *
    FROM OPENJSON(T.JsonColumn, '$.Details')
    WITH
    (
        OrderNumber VARCHAR(200) '$.OrderNumber',
        Quantity INT '$.Quantity'
    )
    WHERE OrderNumber = '1234567'
);

你的情况:

SELECT C.*
FROM CONTENT_RULES AS C
WHERE EXISTS
(
    SELECT *
    FROM OPENJSON(C.CONTENT_RULE, '$.Values')
    WHERE value = 1
);