执行更新语句时如何解决 bind_param() 中的致命错误

Question

我要更新用户个人资料详细信息（姓名、密码、contact_no、电子邮件）。请帮我检查如何改进代码，以便我可以成功更新。

这里是 DbOperations.php updateUser class:

public function updateUser($user_id, $name, $password,$contact_no,$email){
        $stmt = $this->con->prepare("UPDATE `mydb.User` SET `name` = ?, `password`= ? , `contact_no`= ?,`email` = ? WHERE  `user_id` = ? ;");

        $stmt->bind_param("ssisi", $name, $password, $contact_no, $email, $user_id);

        if($stmt->execute()){
                return 1;

        }else{
            return 2;
            }
    }

这里是updateProfile.php

<?php
require_once'../includes/DbOperations.php';

    $response =array();
        if($_SERVER['REQUEST_METHOD']=='POST'){
            if(isset($_POST['user_id'])and
                isset($_POST['name'])and
                    isset($_POST['password'])and
                        isset($_POST['contact_no'])and
                        isset($_POST['email']))

                {//operate the data further
                    $db = new DbOperations();
                    $result=$db->updateUser(
                                        $_POST['user_id'],
                                        $_POST['name'],
                                        $_POST['password'],
                                        $_POST['contact_no'],
                                        $_POST['email']

                                        );
                    if($result == 1){
                                    $response['error']= false;
                                    $response['message'] = "updated successfully";


                    }elseif($result == 2){
                        $response['error']=true;
                        $response['message'] = "updated failed";
                        }
                    }       
            }else{
                $response['error']=true;
                $response['message'] = "empty fileds";

        }


    echo json_encode($response);

错误信息：

`<br />
<b>Fatal error</b>:  Call to a member function bind_param() on a non-object in
<b>C:\xampp\htdocs\Android\includes\DbOperations.php</b> on line
<b>49</b>
<br />`

第 49 行是：$stmt->bind_param("sssss", $name, $password, $contact_no, $email, $user_id);

我正在使用 API 开发人员 POST：

Answer 1

有两点我注意到了

分号;和大括号()在你的SQL，这不应该是它的一部分。而且应该是

"UPDATE `mydb.User` SET `name` = ?, `password`= ? , `contact_no`= ?,`email` = ? WHERE  `user_id` = ?"

因为 userid 和 contact_no 是 integer。那么应该是"ssisi"而不是"sssss"
此外，我建议使用 User 而不是 mydb.User。

Answer 2

update 语句的 set 子句没有括号。只需删除它们，您应该没问题：

$stmt = $this->con->prepare("UPDATE `mydb.User` SET `name` = ?, `password`= ? , `contact_no`= ?,`email` = ? WHERE  `user_id` = ? ;");
# Parentheses removed ------------------------------^------------------------------------------------------^

执行更新语句时如何解决 bind_param() 中的致命错误

How to resolve fatal error in bind_param() when executing update statement

php

mysql

prepared-statement

bindparam