Laravel: 如何在一个查询中写两个查询并从数据库中获取结果？

Question

我有获取当前用户所有已删除邮件的示例代码：

$query1 = $inbox->where('recipient', $user_id)
                ->where('trashed_in_recipient', 1)
                ->where('show_in_recipient', '!=', 1)
                ->orderBy('created_at', 'desc')
                ->paginate($paginate);

$query2 = $inbox->where('sender', $user_id)
                ->where('trashed_in_sender', 1)
                ->where('show_in_sender', '!=', 1)
                ->orderBy('created_at', 'desc')
                ->paginate($paginate);

如何将两个查询合二为一并得到最终结果？

Table结构：

Answer 1

您可以使用函数来定义 WHERE 个组：

$query = $inbox->where(function($query) use ($user_id) {
    $query->where('recipient', $user_id);
    $query->where('trashed_in_recipient', 1);
    $query->where('show_in_recipient', '!=', 1);
})->orWhere(function($query) use ($user_id) {
    $query->where('sender', $user_id);
    $query->where('trashed_in_sender', 1);
    $query->where('show_in_sender', '!=', 1);
})->orderBy('created_at', 'desc')
  ->paginate($paginate);

希望对您有所帮助

Laravel: 如何在一个查询中写两个查询并从数据库中获取结果？

Laravel: How to write two query in one query and get result from database?

php

laravel

eloquent

laravel-eloquent

laravel-5.5