如何从 play 2.6 scala 中的请求中获取 ROUTE_PATTERN

Question

我在 play 2.5 中提取了 ROUTE_PATTERN：

request.tags.get("ROUTE_PATTERN")

现在我更新了 play 2.6，这段代码不再有效了。我在这里阅读了播放文档： What’s new in Play 2.6

我试过了：

object Attrs {
    val RoutePattern: TypedKey[String] = TypedKey("ROUTE_PATTERN")
  }
  request.attrs.get(Attrs.RoutePattern)

总是returnsNone。我如何在 play 2.6 中获取请求的 RoutePattern？

Answer 1

来自2.6 migration guide：

If you used any of the Router.Tags.* tags, you should change your code to use the new Router.Attrs.HandlerDef (Scala)....

This new attribute contains a HandlerDef object with all the information that is currently in the tags. The current tags all correspond to a field in the HandlerDef object....

HandlerDef 中对应旧 ROUTE_PATTERN 标签的字段是 path:

import play.api.routing.{ HandlerDef, Router }
import play.api.mvc.RequestHeader

val handler = request.attrs(Router.Attrs.HandlerDef)
val routePattern = handler.path

如何从 play 2.6 scala 中的请求中获取 ROUTE_PATTERN

How to get ROUTE_PATTERN from request in play 2.6 scala

scala

playframework

playframework-2.6