Bash while 循环中找不到脚本命令错误

Question

我有问题，但仍然无法处理。 :( 这是我的代码

declare -i disk_usage_rate=$(df -h /appdata/SCT_CDR | cut -d '%' -f 1 | awk 'NR==2{print }')

while ["$disk_usage_rate" -gt 80]
do
...
...
done

我从 df -h 命令获取磁盘使用率。但是在 while 循环中我得到了 followig 错误。顺便说一句，它是 bash 脚本。

bash: [84: command not found

我尝试了很多东西，但我还没有解决。

Answer 1

我看到一个错误：在您的 while 行的 '[' 之后和 ']' 之前添加一个 space :

while [ "$disk_usage_rate" -gt 80 ]

好点了吗？

Answer 2

您在 while 循环中使用的方括号附近缺少 space，如下所示 -

declare -i disk_usage_rate=$(df -h /appdata/SCT_CDR | cut -d '%' -f 1 | awk 'NR==2{print }')

while [ "$disk_usage_rate" -gt 80 ]
do
...
...
done

A bit of history: this is because '[' was historically not a shell-built-in but a separate executable that received the expresson as arguments and returned a result. If you didn't surround the '[' with space, the shell would be searching $PATH for a different filename (and not find it) . – Andrew Medico Jun 24 '09 at 1:13

参考 - bash shell script syntax error

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