在 SQL 中加入 2 Table 个变量

Question

如何连接不包含外键列的 2 table 个变量。

DECLARE @InventoryIDList TABLE(ID INT)
DECLARE @ProductSupplierIDList TABLE(ID INT)

异常输出

@InventoryList
--------------
123
456
789
111

@ProductSupplierIDList
--------------
999
888
777
666

@InventoryList    ProductSupplierIDList
---------------------------------------
123             |        999
567             |        888
789             |        777
111             |        666

都是随机数据。我只想将 2 table 变量组合成上面的样子。我尝试了所有类型的连接。但是我需要在没有 null 值的情况下获得上面提到的输出。

我尝试了 CROSS APPLY

SELECT *
FROM @InventoryIDList invList CROSS APPLY @ProductSupplierIDList prdList

但是它给了我 5^2 个元素作为重复的结果。

Answer 1

我猜你需要 Row_Number 和 Full Outer Join，考虑到这两个表之间没有关系

SELECT I.ID,
       P.ID
FROM   (SELECT Rn = Row_number()OVER(ORDER BY ID),*
        FROM   @InventoryList) I
       FULL JOIN (SELECT Rn = Row_number()OVER(ORDER BY ID),*
                  FROM   @ProductSupplierIDList) p
              ON I.RN = P.RN

Answer 2

假设 JOIN 条件相同 "row number" ID 升序：

WITH invList AS (
    SELECT *,
           ROW_NUMBER() OVER (ORDER BY ID) AS RN
    FROM @InventoryIDList),
prdList AS (
    SELECT *,
           ROW_NUMBER() OVER (ORDER BY ID) AS RN
    FROM @ProductSupplierIDList)
SELECT *
FROM invList IL
     JOIN prdList PL ON IL.RN = PL.RN;

Answer 3

由于 ID 不是按顺序排列的，可以是随机的，我建议在 table 变量上使用身份并加入：

DECLARE @InventoryIDList TABLE(JoiningID INT IDENTITY(1,1), ID INT)
DECLARE @ProductSupplierIDList TABLE(JoiningID INT IDENTITY(1,1), ID INT)

INSERT INTO @InventoryIDList 
VALUES 
(123),
(456),
(789),
(111)

INSERT INTO @productsupplierIDList 
VALUES 
(999),
(888),
(777),
(666)


SELECT i.id, p.id
FROM @inventoryIDList i
INNER JOIN @productsupplierIDList p
    oN i.joiningid = p.JoiningID

在 SQL 中加入 2 Table 个变量

Join 2 Table Variables in SQL

tsql

sql-server

join

table-variable