Angular Reactive Form 的深拷贝?

Deep copy of Angular Reactive Form?

我正在尝试构建一个函数来生成给定 FormGroup 的副本。我开始于:

function copyForm(form: FormGroup): FormGroup {
  const copy = new FormGroup({});
  for (let key of Object.keys(form.value)) {
    const control = form.controls[key];

    /* Copy the data from the control into a new control */
    const copyControl = new FormControl({[key]: control.value});

    copy.addControl(key, copyControl);
 }

但如果有 FormArrayFormGroup,那将不起作用。 如果它是递归的,它可能会工作,但我无法很好地处理它。

我也尝试用

解决
function copyForm(form: FormGroup): FormGroup {
  const copy = new FormGroup({});
  for (let key of Object.keys(form.value)) {
    const control = form.controls[key];
    const copyControl = new FormControl({...control.value});
    copy.addControl(key, copyControl);
  }
  return copy;

}

但这不适用于双嵌套 FormGroups、任何 FormArrays 或常规 FormControls...

我也试过:

function copyForm(form: FormGroup): FormGroup {
  const copy = new FormGroup(Object.assign({}, form.value));
  return copy;
}

但这给了我错误:

ERROR TypeError: control.setParent is not a function

我被难住了。

我会这样做:

copyFormControl(control: AbstractControl) {
    if (control instanceof FormControl) {
        return new FormControl(control.value);
    } else if (control instanceof FormGroup) {
        const copy = new FormGroup({});
        Object.keys(control.controls).forEach(key => {
            copy.addControl(key, copyFormControl(control.controls[key]));
        });
        return copy;
    } else if (control instanceof FormArray) {
        const copy = new FormArray([]);
        control.controls.forEach(control => {
            copy.push(copyFormControl(control));
        })
        return copy;
    }
}

我个人使用在这里找到的 lodash cloneDeep() 函数:

https://lodash.com/docs/#cloneDeep

我是这样使用的:

const newFormGroup: any = _.cloneDeep(myFormGroup);

如果你想要它是强类型的,你可以添加 as FormGroup 作为@Andre Elrico 在评论中的建议:

const newFormGroup = _.cloneDeep(myFormGroup) as FormGroup;

这是我想出的深度复制功能,它还保留了每个 AbstractControl 的关联验证器/异步验证器功能和禁用状态。

/**
 * Deep clones the given AbstractControl, preserving values, validators, async validators, and disabled status.
 * @param control AbstractControl
 * @returns AbstractControl
 */
export function cloneAbstractControl<T extends AbstractControl>(control: T): T {
  let newControl: T;

  if (control instanceof FormGroup) {
    const formGroup = new FormGroup({}, control.validator, control.asyncValidator);
    const controls = control.controls;

    Object.keys(controls).forEach(key => {
      formGroup.addControl(key, cloneAbstractControl(controls[key]));
    })

    newControl = formGroup as any;
  }
  else if (control instanceof FormArray) {
    const formArray = new FormArray([], control.validator, control.asyncValidator);

    control.controls.forEach(formControl => formArray.push(cloneAbstractControl(formControl)))

    newControl = formArray as any;
  }
  else if (control instanceof FormControl) {
    newControl = new FormControl(control.value, control.validator, control.asyncValidator) as any;
  }
  else {
    throw new Error('Error: unexpected control value');
  }

  if (control.disabled) newControl.disable({emitEvent: false});

  return newControl;
}

如果您有简单的 FormGroups 仅包含 FormControls(即不包含 FormGroups 或 FormArrays),并且您事先知道它们的结构,那么这是一个简单的解决方案:

注意:通过使用 initaliseFormGroup 初始化原始 FormGroup,您将为每个控件匹配验证器。

initaliseFormGroup(){
    return new FormGroup({
        x : new FormControl('', Validators.required),
        y : new FormControl('', Validators.minLength(10))
    });
}

cloneFormGroup(oldForm: FormGroup){
    let newForm = this.initaliseFormGroup()
    newForm.patchValue(oldForm.value);
    return newForm;
}

如果您有更复杂的表单(带有子 FormGroup),或者想动态克隆它们而不事先知道它们的结构,那么其他答案会更适合。