在 Objective C (iOS) 中向远程推送通知添加消息

Question

如何从动态通知服务获取和显示推送通知中的消息

push: {
    aps =  {
        alert = "My First Notification";
        sound = default;
        Msg = {
            myData = (
                      {
                        Msg = "Awesome";
                        Id = 123;
                        Date = "Jan 18 2018";
                       }
                      );
              };
           };
       }

因为我想在推送通知到达时显示 alert = "My First Notification" 和 Msg = "Awesome"。我不知道如何获取和显示。请帮我解决这个问题。 TIA

我试过下面的代码

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions {
    // Override point for customization after application launch.

    [application registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:(UIUserNotificationTypeSound | UIUserNotificationTypeAlert | UIUserNotificationTypeBadge) categories:nil]];

    [application registerForRemoteNotifications];


    return YES;
}

- (void)application:(UIApplication*)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData*)deviceToken
{
    NSLog(@"My token is: %@", deviceToken);

    NSString *deviceTokenStr = [[[[deviceToken description]
                                  stringByReplacingOccurrencesOfString: @"<" withString: @""]
                                 stringByReplacingOccurrencesOfString: @">" withString: @""]
                                stringByReplacingOccurrencesOfString: @" " withString: @""];

    NSLog(@"Device Token: %@", deviceTokenStr);
}

- (void)application:(UIApplication*)application didFailToRegisterForRemoteNotificationsWithError:(NSError*)error
{
    NSLog(@"Failed to get token, error: %@", error);
}

- (void)application:(UIApplication*)application didReceiveRemoteNotification:(NSDictionary*)userInfo
{
    NSLog(@"Received notification: %@", userInfo);
    NSUserDefaults * loginDefaults = [NSUserDefaults standardUserDefaults];

    UIApplicationState state = [[UIApplication sharedApplication] applicationState];
    if (UIApplicationStateActive == state )
    {

        return;
    }

}

我只想在推送通知中显示它。

Answer 1

首先，UserInfo 是一个 NSDictionary，因此您可以通过按键获取所有需要的值，在您的情况下会是这样的

代码

NSDictionary * aps = [userInfo objectForKey:@"aps"];
NSDictionary * myData = [aps objectForKey:@"Msg"];
//inside of Msg dictionary you have an array of dictionaries
NSArray * arrayOfData = [myData objectForKey:@"myData"];
NSLog(@"%@",[arrayOfData objectAtIndex:0]);
NSDictionary * infoDict = [arrayOfData objectAtIndex:0];
//here we get the message!!!
NSString* message = [infoDict objectForKey:@"Msg"];
//then show your alert
UIAlertController* alertController = [UIAlertController alertControllerWithTitle:NSLocalizedString(@"My First Notification", nil) message:message preferredStyle:UIAlertControllerStyleAlert];
[[[self window] rootViewController] presentViewController:alertController animated:true completion:nil];

此代码未经测试如果有问题请告诉我，但这是我的想法

Answer 2

据我从您的评论中了解到，您希望推送在通知屏幕上显示标题 My First Notification 和消息（或 body）Awesome。为此，您无需在应用程序中编写代码。神奇的是负载的结构。

目前您正在以

的形式发送负载

{
  "aps": {
    "alert": "My First Notification",
    "sound": "default",
    "Msg": {
      "myData": [
        {
          "Msg": "Awesome",
          "Id": 123,
          "Date": "Jan 18 2018"
        }
      ]
    }
  }
}

不会根据 apple docs

在通知屏幕上显示 Awesome 消息

要在通知屏幕上显示 Awesome 消息，您需要指定 body 键。创建如下所示的有效负载并发送此推送，您将在通知屏幕上看到标题和 body。另请阅读上述文档以获取更多信息

{
  "aps": {
    "alert": {
      "title": "My First Notification",
      "body": "Awesome",
      "sound": "default"
    }
  },
  "myData": {
    "Id": 123,
    "Date": "Jan 18 2018"
  }
}

最后我想补充一点，在 android 中我们需要在应用程序中编写代码来显示推送通知，而在 ios 中我们不必编写代码或者更准确地说，我们的应用程序不控制推送的显示方式。这完全取决于使用适当的密钥将数据发送到 APNS 的服务器

在 Objective C (iOS) 中向远程推送通知添加消息

Add message to Remote Push Notification in Objective C (iOS)

ios

objective-c

xcode

apple-push-notifications

objective-c-2.0