beautiful soup 重新解析返回的一组 table 行 beautiful soup

Question

我正在尝试解析第二组数据。我向 gigya 状态页面发出一个获取请求，我解析出对美丽汤很重要的部分。然后我使用 html 的 return 字符串尝试用漂亮的汤解析它但是我得到一个标记错误但是 returned 内容字符串也是一个字符串所以我不确定为什么..

错误

Traceback (most recent call last):
  File "C:\Users\Administraor\workspace\ChronoTrack\get_gigiya.py", line 17, in <module>
    soup2 = BeautifulSoup(rows)
  File "C:\Python27\lib\site-packages\bs4\__init__.py", line 161, in __init__
    markup = markup.read()
TypeError: 'NoneType' object is not callable

代码

import requests
import sys
from bs4 import BeautifulSoup
url = ('https://console.gigya.com/site/apiStatus/getTable.ashx')
r = requests.request('GET', url)
content = str(r.content)

soup = BeautifulSoup(content)
table = soup.findAll('table')
rows = soup.findAll('tr')

rows = rows[8]
soup2 = BeautifulSoup(rows) #this is where it fails
items = soup2.findAll('td')
print items

Answer 1

行soup2 = BeautifulSoup(rows)是不必要的； rows 此时已经是一个 BeautifulSoup.Tag 对象。你可以简单地做：

rows = rows[8]
items = rows.findAll('td')

beautiful soup 重新解析返回的一组 table 行 beautiful soup

beautiful soup re-parse a returned set of table rows beautiful soup

python

beautifulsoup

html-parsing

gigya