python class 如何用不同的名称初始化？

Question

昨天我不得不为 python 项目使用 WMI。我找到 python 库 here。这个库确实有很好的文档记录，并且有很多工作示例。例如：

import wmi
c = wmi.WMI ()

for process in c.Win32_Process ():
  print process.ProcessId, process.Name

或

import wmi
c = wmi.WMI ("some_other_machine")

我很好奇我可以为 WMI class 初始化传递什么样的参数，并查看了源代码。我看起来像 class WMI: 或函数 def WMI()，但是我发现是这样声明的：

#
# class WMI
#
class _wmi_namespace:
  """A WMI root of a computer system. The classes attribute holds a list
  of the classes on offer. This means you can explore a bit with
  things like this::

    c = wmi.WMI ()
    for i in c.classes:
      if "user" in i.lower ():
        print i
  """
  def __init__ (self, namespace, find_classes):
    _set (self, "_namespace", namespace)
    #
    # wmi attribute preserved for backwards compatibility
    #
    _set (self, "wmi", namespace)

    self._classes = None
    self._classes_map = {}
    #
    # Pick up the list of classes under this namespace
    #  so that they can be queried, and used as though
    #  properties of the namespace by means of the __getattr__
    #  hook below.
    # If the namespace does not support SubclassesOf, carry on
    #  regardless
    #
    if find_classes:
      _ = self.classes

如我所见，评论中有解释它是如何工作的，但无论如何我还是看不懂。

Answer 1

WMI 被定义为 wmi.py 中第 1295 行附近的 WMI = connect 并且不是 class，而是 connect() 函数的另一个名称。因此，要查看参数，请查看 connect().

python class 如何用不同的名称初始化？

How does python class initialized with different name?

python

wmi