Swift 相当于 Ruby 的 "Pathname.relative_path_from"

Question

objc 中已经有 KSFileUtilities 的 ks_stringRelativeToURL 方法，非常接近。我正在寻找可以运行 on Linux 的纯 swift 解决方案。

我更喜欢使用 file:// URL 的解决方案，但 String 也可以。

文件系统可以是 case sensitive/insensitive。确定相对路径可能很棘手。

输入和预期输出示例：

| Long Path                      | Relative to Path | Return Value      |
|--------------------------------|------------------|-------------------|
| /usr/X11/agent/47.gz           | /usr/X11         | agent/47.gz       |
| /usr/share/man/meltdown.1      | /usr/share/cups  | ../man/meltdown.1 |
| file:///var/logs/x/y/z/log.txt | file:///var/logs | x/y/z/log.txt     |

Swift 已经有 FileManager.getRelationship(_:of:in:toItemAt:)，但它没有 return 相对路径。

Answer 1

Swift标准库或基础框架，据我所知

这是URL的扩展方法的可能实现：

extension URL {
    func relativePath(from base: URL) -> String? {
        // Ensure that both URLs represent files:
        guard self.isFileURL && base.isFileURL else {
            return nil
        }

        // Remove/replace "." and "..", make paths absolute:
        let destComponents = self.standardized.pathComponents
        let baseComponents = base.standardized.pathComponents

        // Find number of common path components:
        var i = 0
        while i < destComponents.count && i < baseComponents.count
            && destComponents[i] == baseComponents[i] {
                i += 1
        }

        // Build relative path:
        var relComponents = Array(repeating: "..", count: baseComponents.count - i)
        relComponents.append(contentsOf: destComponents[i...])
        return relComponents.joined(separator: "/")
    }
}

我的测试代码：

func test(_ p1: String, _ p2: String) {
    let u1 = URL(fileURLWithPath: p1)
    let u2 = URL(fileURLWithPath: p2)
    print(u1.relativePath(from: u2) ?? "<ERROR>")
}
test("/usr/X11/agent/47.gz",      "/usr/X11")        // "agent/47.gz"
test("/usr/share/man/meltdown.1", "/usr/share/cups") // "../man/meltdown.1"
test("/var/logs/x/y/z/log.txt",   "/var/logs")       // "x/y/z/log.txt"

备注：

“。”和 ".." 在给定的 URLs 被删除，并且相关文件 URLs 是绝对的（都使用 URL 的 standardized 方法）。
区分大小写未处理。
假设基础URL代表一个目录。

附录： @neoneye 将其包装到 Swift 包中： SwiftyRelativePath.

Answer 2

Martin R 的答案是正确的。但是，当基础 URL 本身就是一个文件时，我遇到了一个问题。因此，我做了一些调整：

func relativePath(from base: URL) -> String? {
    // Ensure that both URLs represent files:
    guard self.isFileURL && base.isFileURL else {
        return nil
    }

    //this is the new part, clearly, need to use workBase in lower part
    var workBase = base
    if workBase.pathExtension != "" {
        workBase = workBase.deletingLastPathComponent()
    }

    // Remove/replace "." and "..", make paths absolute:
    let destComponents = self.standardized.resolvingSymlinksInPath().pathComponents
    let baseComponents = workBase.standardized.resolvingSymlinksInPath().pathComponents

    // Find number of common path components:
    var i = 0
    while i < destComponents.count &&
          i < baseComponents.count &&
          destComponents[i] == baseComponents[i] {
            i += 1
    }

    // Build relative path:
    var relComponents = Array(repeating: "..", count: baseComponents.count - i)
    relComponents.append(contentsOf: destComponents[i...])
    return relComponents.joined(separator: "/")
}

我的测试用例有点扩展。案例 4 是我进行此小更改的触发因素。

 func testRelativePath() {
    // This is an example of a functional test case.
    // Use XCTAssert and related functions to verify your tests produce the correct results.
    func test(_ p1: String, _ p2: String,_ result: String,_ nr: Int) {
        let u1 = URL(fileURLWithPath: p1)
        let u2 = URL(fileURLWithPath: p2)
        let r = u1.relativePath(from: u2)!
        XCTAssert( r == result,"\(nr): '\(r)' != '\(result)'")
    }
    test("/usr/X11/agent/47.gz",      "/usr/X11","agent/47.gz", 1)
    test("/usr/share/man/meltdown.1", "/usr/share/cups", "../man/meltdown.1",2 )
    test("/var/logs/x/y/z/log.txt",   "/var/logs", "x/y/z/log.txt",3)
    test("/usr/embedded.jpg",   "/usr/main.html", "embedded.jpg",4)
    test("/usr/embedded.jpg",   "/usr", "embedded.jpg",5)
    test("~/Downloads/resources",   "~/", "Downloads/resources",6)
    test("~/Downloads/embedded.jpg",   "~/Downloads/main.html", "embedded.jpg",7)
    test("/private/var/logs/x/y/z/log.txt", "/var/logs", "x/y/z/log.txt",8)
 }

Answer 3

我使用的是 Wizard of Kneup 的版本，但是当基本目录有扩展名时遇到了问题。所以我添加代码来检查路径是否存在并且是一个目录。

public extension URL 
{
    func relativePath(from base: URL) -> String?
    {
        // Ensure that both URLs represent files:
        guard self.isFileURL &&
              FileManager.default.fileExists(atPath: self.path) else
        {
            NSLog("self is not a fileURL or it does not exists")
            return nil
        }

        var isDir = ObjCBool(true)
        guard FileManager.default.fileExists(atPath: base.path, isDirectory: &isDir) &&
              isDir.boolValue else
        {
            NSLog("base is not a directory or it does not exists")
            return nil
        }           


        // Remove/replace "." and "..", make paths absolute:
        let destComponents = self.resolvingSymlinksInPath().pathComponents
        let baseComponents = base.resolvingSymlinksInPath().pathComponents

        // Find number of common path components:
        let i = Set(destComponents).intersection(Set(baseComponents)).count

        // Build relative path:
        let relComponents = Array(repeating: "..", count: baseComponents.count - i) +
                            destComponents[i...]
        return relComponents.joined(separator: "/")
    }
}

Swift 相当于 Ruby 的 "Pathname.relative_path_from"

Swift equivalent of Ruby's "Pathname.relative_path_from"

url

nsurl

nsfilemanager

swift

server-side-swift