如何在 Oracle 10g 中使用 UTL_FILE 打印在 table 中插入的行数?

How do I print number of rows inserted in a table using UTL_FILE in Oracle 10g?

我在数据库中有一个 table TEST_TABLE,我想使用存储过程在其中插入一些值。 SP 完成后如何打印插入 TEST_TABLE 中的行数??...我想使用 UTL_FILE 包执行此操作并希望生成一个文本文件来监视数据加载。

这是一个基于 HR 架构的示例 - 我将部门 table 中的一些行插入到 DEPT_TEST 中。可以通过 SQL%ROWCOUNT 检索插入的行数,其中 returns 最后一个 DML 语句处理的行数(调用 SQL%ROWCOUNT 之前最后执行的)。

程序本身有点愚蠢 - 它"simulates" 我认为你的做法 - 插入一些行,然后插入更多行,等等。UTL_FILE 用法是可以理解的,我想(哎呀,FOPENFWRITE 会做什么?)。我正在将值写入位于我的 EXT_DIR 目录(实际上是 C:\TEMP)的 TEST.TXT。

请注意 - 如果您还没有它 - 您应该首先创建目录(以 SYS 身份连接)并授予 READ/WRITE 权限给将要使用它的用户(在我的例子中是 HR)。

好的,我们开始吧:

SQL> show user
USER is "SYS"
SQL> create directory ext_dir as 'c:\temp';

Directory created.

SQL> grant read, write on directory ext_dir to hr;

Grant succeeded.

SQL> connect hr/hr@xe
Connected.

SQL> create table dept_test as select * From departments where 1 = 2;

Table created.

SQL> declare
  2    l_file utl_file.file_type;
  3  begin
  4    l_file := utl_file.fopen('EXT_DIR', 'test.txt', 'w');
  5
  6    insert into dept_test (department_id, department_name, manager_id, location_id)
  7      select department_id, department_name, manager_id, location_id
  8        from departments
  9        where department_id between 0 and 150;
 10      utl_file.put_line(l_file, to_char(sysdate, 'hh24:mi:ss') ||
 11        ': Inserted ' || sql%rowcount || ' rows');
 12
 13    insert into dept_test (department_id, department_name, manager_id, location_id)
 14      select department_id, department_name, manager_id, location_id
 15        from departments
 16        where department_id between 151 and 300;
 17      utl_file.put_line(l_file, to_char(sysdate, 'hh24:mi:ss') ||
 18        ': Inserted ' || sql%rowcount || ' rows');
 19
 20    utl_file.fclose(l_file);
 21  end;
 22  /

PL/SQL procedure successfully completed.

SQL> $type c:\temp\test.txt
12:32:51: Inserted 15 rows
12:32:51: Inserted 12 rows

SQL>

但是,如果可以的话,我会建议另一种方法 - 登录数据库。为此,您需要一个日志 table 和一个使用 autonomous_transaction pragma 的过程(以便您可以提交插入,而不影响调用者执行的事务)。

SQL> CREATE TABLE a1_log
  2  (
  3     id      NUMBER,
  4     datum   DATE,
  5     desc    VARCHAR2 (200)
  6  );

Table created.

SQL> CREATE SEQUENCE seqlog START WITH 1 INCREMENT BY 1;

Sequence created.

SQL> CREATE OR REPLACE PROCEDURE a1_p_log (par_description IN VARCHAR2)
  2  IS
  3     PRAGMA AUTONOMOUS_TRANSACTION;
  4  BEGIN
  5     INSERT INTO a1_log
  6        SELECT seqlog.NEXTVAL, SYSDATE, par_description FROM DUAL;
  7
  8     COMMIT;
  9  END a1_p_log;
 10  /

Procedure created.

现在,最初的 "inserting" 过程如下所示:

SQL> begin
  2    insert into dept_test (department_id, department_name, manager_id, location_id)
  3      select department_id, department_name, manager_id, location_id
  4        from departments
  5        where department_id between 0 and 150;
  6      a1_p_log('Inserted ' || sql%rowcount || ' rows');
  7
  8    insert into dept_test (department_id, department_name, manager_id, location_id)
  9      select department_id, department_name, manager_id, location_id
 10        from departments
 11        where department_id between 151 and 300;
 12      a1_p_log('Inserted ' || sql%rowcount || ' rows');
 13  end;
 14  /

PL/SQL procedure successfully completed.

SQL> col description format a40
SQL> alter session set nls_date_format = 'hh24:mi:ss';

Session altered.

SQL> select * From a1_log;

        ID DATUM    DESCRIPTION
---------- -------- ----------------------------------------
         1 12:52:08 Inserted 15 rows
         2 12:52:08 Inserted 12 rows

SQL>

在我看来,这是一个更简单的选项,我建议您使用它而不是 UTL_FILE 选项,但是 - 最后,这取决于您。