find() 等同于帆

Question

我想执行这样的查询，

select * from user where user.status = 'ban' and
user.status = 'new' and
user.username like 'fo%' // in code I will get this from req.param('user')

我知道怎么做了，

var username = req.param('user');
var status = req.param('status');
User.find().where({ status : [status, 'new'], username : username }).exec(function(err, users){
        console.log(users);
});

但我不知道如何使用 "like" 作为用户名。

我该怎么办。谢谢

Answer 1

var username = req.param('user');
var status = req.param('status');
User.find({
    status: [status, 'new'],
    username: {
        'startsWith': username
    }
}).exec(function(err, users) {
    console.log(users);
});

试试看

作为参考，这里有一个 link 关于水线查询格式的文档 https://github.com/balderdashy/waterline-docs/blob/master/query-language.md

find() 等同于帆

find() with equal and like in sails

node.js

sails.js

waterline