Mvc 核心 2.0 中的 HttpGet returns 404

HttpGet returns 404 in Mvc core 2.0

public class SurveyController : Controller
{
    public IActionResult Index()
    {
        var surveys = new List<int>{1};
        return View(Surveys);
    }

    [HttpGet("conditions")]
    public IActionResult GetConditions()
    {
        List<int> Conditions = new List<int{1};
        return View("Conditions",Conditions);
    }
}

现在浏览量低于

Views/Survey/Index.cshtml

Views/Survey/Conditions.cshtml

路线 Survey/conditions 正在返回 404

有人知道吗?

我的startup.cs是-

public void Configure(IApplicationBuilder app, IHostingEnvironment env)
{
    if (env.IsDevelopment())
    {
        app.UseDeveloperExceptionPage();
        app.UseBrowserLink();
        app.UseDatabaseErrorPage();
    }
    else
    {
        app.UseExceptionHandler("/Home/Error");
    }

    app.UseStaticFiles();

    app.UseAuthentication();

    app.UseMvc(routes =>
    {
        routes.MapRoute(
            name: "default",
            template: "{controller=Home}/{action=Index}/{id?}");
    });   
}

试试这个:

public class SurveyController : Controller
{
    public IActionResult Index()
    {
        var surveys = new List<int>{1};
        return View(Surveys);
    }

    [HttpGet("conditions")]
    [Route("Survey/conditions")]
    public IActionResult GetConditions()
    {
        List<int> Conditions = new List<int{1};
        return View();
    }
}

或更改控制器中函数的名称:

public class SurveyController : Controller
{
    public IActionResult Index()
    {
        var surveys = new List<int>{1};
        return View(Surveys);
    }

    [HttpGet("conditions")]
    public IActionResult conditions()
    {
        List<int> Conditions = new List<int{1};
        return View();
    }
}

或者在浏览器的浏览器路由中写函数名:

路线 = 'Survey/GetConditions'

你对动作的属性:

[HttpGet("conditions")]

指定您希望 URL 为 http://whatever/conditions。相反,你应该使用:

[HttpGet("/survey/conditions")]

如果您希望以更好的粒度控制路由,则应改用 Route 属性。例如:

[Route("[controller]")] //Set the prefix for subsequent route attributes
public class SurveyController : Controller
{
    [Route("conditions")]
    public IActionResult GetConditions()
    {
        List<int> Conditions = new List<int{1};
        return View("Conditions",Conditions);
    }
}

引用Routing to Controller Actions