如何使用自定义转换器？

Question

我想解析时间来自

<monday>
    <item>
        <time>00:00:00</time>
    </item>
...
</monday>

只要我将物品定义为

@Root(strict = false) 
private static class Item {
     @Element(name = "time") 
     @Convert(TimeConverter.class) 
     private Long time;
}

我的转换器

public class TimeConverter implements org.simpleframework.xml.convert.Converter<Long> {

    SimpleDateFormat df = new SimpleDateFormat("HH:mm:ss");

    @Override 
    public Long read(InputNode node) throws Exception {
        try {
            String value = node.getValue();

          return df.parse(value).getTime();
        } catch (Exception e) {
          Log.e("mcheck", "read:  ", e);
          return 0L;
        }
    }

    @Override 
    public void write(OutputNode node, Long value) throws Exception {
        try {
            String v = df.format(new Date(value));
            node.setValue(v);
        } catch (Exception e) {
            Log.e("mcheck", "write:  ", e);
        }
    }
}

然而，当我解析它时，我收到

retrofit.RetrofitError: java.lang.NumberFormatException: Invalid long: "00:00:00"

由于这个异常没有在转换器中的 try-catch 块中捕获，我假设解析器根本不访问转换器。

我的改装 1.9 调用

OkHttpClient httpClient = new OkHttpClient();
RestAdapter.Builder builder = new RestAdapter.Builder();
builder.setEndpoint(url);
builder.setLogLevel(RestAdapter.LogLevel.FULL);
builder.setConverter(new SimpleXMLConverter());
builder.setClient(new OkClient(httpClient));
RestAdapter restAdapter = builder.build();
ChansonApi api = restAdapter.create(ChansonApi.class);
api.getStreamProgram(new Callback<StreamProgram>() {
    @Override
    public void success(StreamProgram streamProgram, Response response) {
        if(streamProgram!=null){
            Log.e("mcheck", "success:  "+streamProgram.getProgram());
        }
    }

    @Override 
    public void failure(RetrofitError error) {
        Log.e("mcheck", "failure:  ",error);
    }
});

Answer 1

问题出在 proguard 设置中。我必须将 TimeConverter 添加到 -keep class list

如何使用自定义转换器？

How to use custom converter?

java

simple-framework

retrofit