在 java/android 中获取带有匹配器的字符串列表

Question

我有一个像

这样的字符串

number +919999999990  time at:07:42:45 on 10.04.2014, number
+919999999991 time at:08:42:45 on 11.05.2014,  number +919999999992 time at:075:42:45 on 05.03.2014 , number +9199999999913 ,time at:27:40:45 on 09.04.2015.

我必须检索所有 phone-数字、日期和时间。我打算使用模式和匹配器。

我的密码是

String extra1="number +919999999990  time at:07:42:45 on 10.04.2014, number +919999999991 time at:08:42:45 on 11.05.2014, number +919999999992 time at:075:42:45 on 05.03.2014 , number +9199999999913 ,time at:27:40:45 on 09.04.2015.";
Pattern pattern = Pattern.compile("\+\d{12}");
Matcher matcher = pattern.matcher(extra1);
System.out.println("matcher.groupCount() "+matcher.groupCount());
if (matcher.find()) {
    while(matcher.find()) {
        System.out.println(matcher.group());
    }   
} else {
     System.out.println("Not Found");
}

根据 this and this 它应该打印所有 phone 数字。但我只得到第一个 phone 号码。

任何人都可以提出解决方案...

Answer 1

如果您删除将使用第一个数字的“if (match...)”语句，它对我来说工作正常：

    String extra1 = "number +919999999990  time at:07:42:45 on 10.04.2014, number +919999999991 time at:08:42:45 on 11.05.2014, number +919999999992 time at:075:42:45 on 05.03.2014 , number +9199999999913 ,time at:27:40:45 on 09.04.2015.";
    Pattern pattern = Pattern.compile("\+\d{12}");
    Matcher matcher = pattern.matcher(extra1);
    System.out.println("matcher.groupCount() " + matcher.groupCount());
    while (matcher.find()) {
        System.out.println(matcher.group());
    }

输出：

matcher.groupCount() 0
+919999999990
+919999999991
+919999999992
+919999999991

在 java/android 中获取带有匹配器的字符串列表

get list of string with matcher in java/android

java

android

string

list

matcher