当组在 MS SQL 服务器(连续)中重复时,按组删除除第一个和最后一个值以外的所有值

Removing All but the first and last values by group when the group is repeated in MS SQL Server (contiguous)

我们有一个聊天系统,有时每秒为聊天期间的每个事件生成多个事件日志。问题是这些消耗了大量的数据存储(这在该平台上非常昂贵),我们希望简化我们实际存储的内容并删除真正不需要的东西。

为此,有一个事件类型表示聊天在队列中的位置。我们不关心每个位置,只要它们不干预该聊天的事件即可。因此,我们只想保留每个不同组中的第一个和最后一个,在该组中没有其他事件类型可以在那个时期获得 "total time in queue"。

更复杂的是,客户可以在按部门转移时进出队列,因此同一个聊天可以有多个队列位置记录块。我试过使用 FIRST_VALUE 和 LAST_VALUE 并且它让我大部分时间都在那里,但是当我们遇到这些事件的两个不同块的情况时失败了。

这是生成测试数据的脚本:

<!-- language: lang-sql -->
    CREATE TABLE #testdata (
    id varchar(18),
    name varchar(8),
    [type] varchar(20),
    livechattranscriptid varchar(18),
    groupid varchar(40)) 

INSERT INTO #testdata (id,name,[type],livechattranscriptid,groupid) VALUES 
('0DZ14000003I2pOGAS','34128314','ChatRequest','57014000000ltfIAAQ','57014000000ltfIAAQChatRequest'),
('0DZ14000003IGmQGAW','34181980','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IHbqGAG','34185171','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003ILuHGAW','34201743','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IQ6cGAG','34217778','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IR7JGAW','34221794','PushAssignment','57014000000ltfIAAQ','57014000000ltfIAAQPushAssignment'),
('0DZ14000003IiDnGAK','34287448','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IiDoGAK','34287545','PushAssignment','57014000000ltfIAAQ','57014000000ltfIAAQPushAssignment'),
('0DZ14000003Iut5GAC','34336044','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003Iv7HGAS','34336906','Accept','57014000000ltfIAAQ','57014000000ltfIAAQAccept')

这里尝试识别任何按名称字段排序并按转录 ID 分组的组的第一个和最后一个 ID:

select *,FIRST_VALUE(id) OVER(Partition BY groupid order by livechattranscriptid,name asc) as firstinstancegroup,
    LAST_VALUE(id) OVER(Partition BY groupid order by livechattranscriptid,name asc RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) as lastinstancegroup from #testdata order by livechattranscriptid,name

问题是,它为整个组的所有记录提供了相同的第一个和最后一个 ID,而不是将每组 Enqueue 记录视为一个不同的组。我如何将 Enqueue 的每个不同的分组实例视为一个唯一的组?

这是一个类似的解决方案Grouping contiguous table data

不漂亮,但您会发现基于 OP 的逻辑。同一列上的连续数据

declare @mytable table (
    id varchar(18),
    name varchar(8),
    [type] varchar(20),
    livechattranscriptid varchar(18),
    groupid varchar(100)) 

INSERT INTO @mytable (id,name,[type],livechattranscriptid,groupid) VALUES 
('0DZ14000003I2pOGAS','34128314','ChatRequest','57014000000ltfIAAQ','57014000000ltfIAAQChatRequest'),
('0DZ14000003IGmQGAW','34181980','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IHbqGAG','34185171','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003ILuHGAW','34201743','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IQ6cGAG','34217778','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IR7JGAW','34221794','PushAssignment','57014000000ltfIAAQ','57014000000ltfIAAQPushAssignment'),
('0DZ14000003IiDnGAK','34287448','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003IiDoGAK','34287545','PushAssignment','57014000000ltfIAAQ','57014000000ltfIAAQPushAssignment'),
('0DZ14000003Iut5GAC','34336044','Enqueue','57014000000ltfIAAQ','57014000000ltfIAAQEnqueue'),
('0DZ14000003Iv7HGAS','34336906','Accept','57014000000ltfIAAQ','57014000000ltfIAAQAccept')


;with myend as (   --- get all ends
 select 
 *
  from 
 (select 
   iif(groupid <> lead(groupid,1,groupid) over (order by name),
     id,
     'x') [newid],name
 from @mytable
 )x 
 where newid <> 'x'
 )
 , mystart as   -- get all starts
 (
 select 
  *
    from 
 (select 
   iif(groupid <> lag(groupid,1,groupid) over (order by name),
     id,
     'x') [newid], name,type,livechattranscriptid
 from @mytable
 )x 
 where newid <> 'x'
 )  ,
 finalstart as (   --- get all starts including the first row

  select id, 
    name,type,livechattranscriptid,
    row_number() over (order by name) rn
    from (
    select id,name,type,livechattranscriptid 
    from (
    select top 1 id, name,type,livechattranscriptid
    from @mytable
    order by name) x
    union all
    select newid,name,type,livechattranscriptid from mystart
    ) y

 ),
 finalend as   -- get all ends and add the last row
   (

  select id, 
    row_number() over (order by name) rn
    from (
    select id,name from (
    select top 1 id,name
    from @mytable
    order by name desc) x
    union all
    select newid,name from myend
    ) y
  )
select 
  s.id [startid]
  ,s.name
  ,s.type
  ,s.livechattranscriptid
  ,e.id [lastid]
   from    
  finalend e
  inner join finalstart s 
     on   e.rn = s.rn    --- bind the two results over the positions or row number