图像大小调整中的逻辑错误

Question

我正在使用以下代码，它负责使用 python 的枕头库更改图像分辨率。我正在 aws lambda 上部署代码。代码运行良好，但在调整大小时存在一个简单的逻辑缺陷。该代码旨在按如下方式工作： 1.上传图片到S3 bucket 2.代码将图像调整为2个不同的尺寸并将其上传到不同的存储桶。

但是代码以相同的尺寸上传了 2 张图片，我无法理解为什么

from __future__ import print_function
import boto3
import os
import sys
import uuid
from PIL import Image
import PIL.Image

s3_client = boto3.client('s3')

def resize_image_DOG(image_path, resized_path):
    with Image.open(image_path) as image:
        dim=(3840,2160)
        image.resize(dim)
        image.save(resized_path)

def resize_image_CAT(image_path, resized_path):
    with Image.open(image_path) as image:
        dim=(1920,1080)
        image.resize(dim)
        image.save(resized_path)


def handler(event, context):
    for record in event['Records']:
        bucket = record['s3']['bucket']['name']
        key = record['s3']['object']['key'] 
        download_path = '/tmp/{}{}'.format(uuid.uuid4(), key)
        upload_path_1 = '/tmp/resized-{}{}'.format('test1',key)
        upload_path_2 = '/tmp/resized-{}{}'.format('test2',key)

        s3_client.download_file(bucket, key, download_path)

        resize_image_DOG(download_path, upload_path_1)
        resize_image_CAT(download_path, upload_path_2)

        s3_client.upload_file(upload_path_1, '{}resized'.format(bucket), key+'xxxhdpi-3840*2160'+'.png')

        s3_client.upload_file(upload_path_2, '{}resized'.format(bucket), key+'xxxhdpi-1920*1080'+'.png')

上传到resized bucket中的2张resized images尺寸相同，即第一个resize_image_DOG尺寸（3340x2160）只有，但名称正确，请帮助

Answer 1

我查看了 pillow 文档：image.resize() returns 调整大小的图像，并没有改变传递的图像。

所以应该是

image = image.resize(dim)

图像大小调整中的逻辑错误

Logical error in image resizing

python

image

amazon-s3

amazon-web-services

pillow