简单 Google App Engine 任务队列教程？烧瓶/Python/GAE

Question

我什至无法让任务队列触发简单的打印语句。

不知道是不是我的app结构不对...

最简单的任务队列示例及其结构是什么？

因为这对我不起作用：

@app.route('/task', methods=["GET", "POST"])
def testtask():
  print "Hi, I'm calling the task"
  taskqueue.add(
    url='/execute_task'
  )
  return "I called the task"

@app.route('/execute_task', methods=["GET", "POST"])
def execute_task():
  print "I'm executing the task"
  return "I excecuted the task"

两条路线都在app.yaml文件中：

- url: /execute_task
  script: app.app
  login: admin
- url: /task
  script: app.app
  login: admin

在终端中：

Hi, I'm calling the task INFO 2018-01-28 23:00:49,521 module.py:788] default: "GET /task HTTP/1.1" 200 17

http://localhost:8000/taskqueue

显示：

队列名称最大速率桶大小队列中最旧的任务 (UTC) 任务

默认 5.00/s 5 2018/01/28 22:59:59（0:04:44 前）2

Answer 1

向任务显示的 print 语句没有意义。你永远不会看到它。只有任务可以看到它。让任务通过日志与您对话。

看看这是否更有意义：

from flask import Response
from google.appengine.api import taskqueue
import logging

@app.route('/task', methods=["GET", "POST"])
def testtask():
  logging.info("sending task to queue in testtask...")
  taskqueue.add(
    url    = "/execute_task",
    name   = "task_name_here",
    method = "POST",
    params = {
      "sender": "me"
    }
  )
  return Response("sending task to queue... Check logs", mimetype='text/plain', status=200)

@app.route('/execute_task', methods=["GET", "POST"])
def execute_task():
  logging.info("I did the task")
  logging.info("params: {}".format(request.form))
  return Response("did it. You'll never see this message", mimetype='text/plain', status=200)

简单 Google App Engine 任务队列教程？烧瓶/Python/GAE

Simple Google App Engine Task Queue tutorial? Flask/ Python/ GAE

python

google-app-engine

task-queue