如何使用 cuda DevicePtr 作为加速数组

Question

我正在尝试使用 cuda DevicePtr (which is called a CUdeviceptr in CUDA-land) returned from foreign code as an accelerate Array with accelerate-llvm-ptx。

我在下面编写的代码有些工作：

import Data.Array.Accelerate
       (Acc, Array, DIM1, Z(Z), (:.)((:.)), use)
import qualified Data.Array.Accelerate as Acc
import Data.Array.Accelerate.Array.Data
       (GArrayData(AD_Float), unsafeIndexArrayData)
import Data.Array.Accelerate.Array.Sugar
       (Array(Array), fromElt, toElt)
import Data.Array.Accelerate.Array.Unique
       (UniqueArray, newUniqueArray)
import Data.Array.Accelerate.LLVM.PTX (run)
import Foreign.C.Types (CULLong(CULLong))
import Foreign.CUDA.Driver (DevicePtr(DevicePtr))
import Foreign.ForeignPtr (newForeignPtr_)
import Foreign.Ptr (intPtrToPtr)

-- A foreign function that uses cuMemAlloc() and cuMemCpyHtoD() to
-- create data on the GPU.  The CUdeviceptr (initialized by cuMemAlloc)
-- is returned from this function.  It is a CULLong in Haskell.
--
-- The data on the GPU is just a list of the 10 floats
-- [0.0, 1.0, 2.0, ..., 8.0, 9.0]
foreign import ccall "mytest.h mytestcuda"
  cmyTestCuda :: IO CULLong

-- | Convert a 'CULLong' to a 'DevicePtr'.
--
-- A 'CULLong' is the type of a CUDA @CUdeviceptr@.  This function
-- converts a raw 'CULLong' into a proper 'DevicePtr' that can be
-- used with the cuda Haskell package.
cullongToDevicePtr :: CULLong -> DevicePtr a
cullongToDevicePtr = DevicePtr . intPtrToPtr . fromIntegral

-- | This function calls 'cmyTestCuda' to get the 'DevicePtr', and
-- wraps that up in an accelerate 'Array'.  It then uses this 'Array'
-- in an accelerate computation.
accelerateWithDataFromC :: IO ()
accelerateWithDataFromC = do
  res <- cmyTestCuda
  let DevicePtr ptrToXs = cullongToDevicePtr res
  foreignPtrToXs <- newForeignPtr_ ptrToXs
  uniqueArrayXs <- newUniqueArray foreignPtrToXs :: IO (UniqueArray Float)
  let arrayDataXs = AD_Float uniqueArrayXs :: GArrayData UniqueArray Float
  let shape = Z :. 10 :: DIM1
      xs = Array (fromElt shape) arrayDataXs :: Array DIM1 Float
      ys = Acc.fromList shape [0,2..18] :: Array DIM1 Float
      usedXs = use xs :: Acc (Array DIM1 Float)
      usedYs = use ys :: Acc (Array DIM1 Float)
      computation = Acc.zipWith (+) usedXs usedYs
      zs = run computation
  putStrLn $ "zs: " <> show z

编译和运行这个程序时，它正确地打印出结果：

zs: Vector (Z :. 10) [0.0,3.0,6.0,9.0,12.0,15.0,18.0,21.0,24.0,27.0]

但是，通过阅读 accelerate 和 accelerate-llvm-ptx 源代码，似乎不应该这样工作。

在大多数情况下，加速Array似乎携带一个指向主机内存中数组数据的指针，而Unique value to uniquely identify the Array. When performing Acc计算，加速会将数组数据从主机内存加载到GPU中根据需要存储内存，并使用 Unique.

索引的 HashMap 对其进行跟踪

在上面的代码中，我直接使用指向 GPU 数据的指针创建了一个 Array。这似乎不应该工作，但它似乎在上面的代码中工作。

但是，有些东西不起作用。例如，尝试打印 xs（我的 Array 带有指向 GPU 数据的指针）失败并出现段错误。这是有道理的，因为 Array 的 Show 实例只是尝试 peek 来自 HOST 指针的数据。这失败了，因为它不是主机指针，而是 GPU 指针：

-- Trying to print xs causes a segfault.
putStrLn $ "xs: " <> show xs

有没有合适的方法获取 CUDA DevicePtr 并直接将其用作加速器 Array？

Answer 1

实际上，令我惊讶的是上面的方法已经如此有效；我无法复制那个。

这里的一个问题是设备内存与执行上下文隐式关联；一个上下文中的指针在不同的上下文中无效，即使在同一 GPU 上也是如此（除非您在这些上下文之间明确启用对等内存访问）。

所以，这个问题实际上有两个组成部分：

以Accelerate理解的方式导入国外数据；和
确保后续的 Accelerate 计算是在可以访问此内存的上下文中执行的。

解决方案

这是我们将用于在 GPU 上生成数据的 C 代码：

#include <cuda.h>
#include <stdio.h>
#include <stdlib.h>

CUdeviceptr generate_gpu_data()
{
  CUresult    status = CUDA_SUCCESS;
  CUdeviceptr d_arr;

  const int N = 32;
  float h_arr[N];

  for (int i = 0; i < N; ++i) {
    h_arr[i] = (float)i;
  }

  status = cuMemAlloc(&d_arr, N*sizeof(float));
  if (CUDA_SUCCESS != status) {
    fprintf(stderr, "cuMemAlloc failed (%d)\n", status);
    exit(1);
  }

  status = cuMemcpyHtoD(d_arr, (void*) h_arr, N*sizeof(float));
  if (CUDA_SUCCESS != status) {
    fprintf(stderr, "cuMemcpyHtoD failed (%d)\n", status);
    exit(1);
  }

  return d_arr;
}

以及使用它的 Haskell/Accelerate 代码：

{-# LANGUAGE ForeignFunctionInterface #-}

import Data.Array.Accelerate                                        as A
import Data.Array.Accelerate.Array.Sugar                            as Sugar
import Data.Array.Accelerate.Array.Data                             as AD
import Data.Array.Accelerate.Array.Remote.LRU                       as LRU

import Data.Array.Accelerate.LLVM.PTX                               as PTX
import Data.Array.Accelerate.LLVM.PTX.Foreign                       as PTX

import Foreign.CUDA.Driver                                          as CUDA

import Text.Printf

main :: IO ()
main = do
  -- Initialise CUDA and create an execution context. From this we also create
  -- the context that our Accelerate programs will run in.
  --
  CUDA.initialise []
  dev <- CUDA.device 0
  ctx <- CUDA.create dev []
  ptx <- PTX.createTargetFromContext ctx

  -- When created, a context becomes the active context, so when we call the
  -- foreign function this is the context that it will be executed within.
  --
  fp  <- c_generate_gpu_data

  -- To import this data into Accelerate, we need both the host-side array
  -- (typically the only thing we see) and then associate this with the existing
  -- device memory (rather than allocating new device memory automatically).
  --
  -- Note that you are still responsible for freeing the device-side data when
  -- you no longer need it.
  --
  arr@(Array _ ad) <- Sugar.allocateArray (Z :. 32) :: IO (Vector Float)
  LRU.insertUnmanaged (ptxMemoryTable ptx) ad fp

  -- NOTE: there seems to be a bug where we haven't recorded that the host-side
  -- data is dirty, and thus needs to be filled in with values from the GPU _if_
  -- those are required on the host. At this point we have the information
  -- necessary to do the transfer ourselves, but I guess this should really be
  -- fixed...
  --
  -- CUDA.peekArray 32 fp (AD.ptrsOfArrayData ad)

  -- An alternative workaround to the above is this no-op computation (this
  -- consumes no additional host or device memory, and executes no kernels).
  -- If you never need the values on the host, you could ignore this step.
  --
  let arr' = PTX.runWith ptx (use arr)

  -- We can now use the array as in a regular Accelerate computation. The only
  -- restriction is that we need to `run*With`, so that we are running in the
  -- context of the foreign memory.
  --
  let r = PTX.runWith ptx $ A.fold (+) 0 (use arr')

  printf "array is: %s\n" (show arr')
  printf "sum is:   %s\n" (show r)

  -- Free the foreign memory (again, it is not managed by Accelerate)
  --
  CUDA.free fp


foreign import ccall unsafe "generate_gpu_data"
  c_generate_gpu_data :: IO (DevicePtr Float)

如何使用 cuda DevicePtr 作为加速数组

how to use a cuda DevicePtr as an accelerate Array

haskell

cuda

gpu

ffi

accelerate-haskell

解决方案