AssertJ 断言异常抛出或结果

Question

我有一个测试用例，我正在使用执行程序服务并调用多个可调用线程。这些线程可能会导致调用成功或可能会出现异常（这是预期的行为）。我需要断言未来的对象要么抛出异常，要么 return 正确响应。

for(Future<Resp> future : futureList) {
Assertions.assertThatThrownBy(() -> 
futureResponse.get()).isInstanceOf(ExecutionException.class);
// or
Assertions.assertThat(futureResponse.get()).isEqualTo(RespObj);
}

如何断言此 "OR" 行为？

Answer 1

您可以使用 try catch 块：

  for(Future<Resp> future : futureList) {
        try {
            Assertions.assertThat(futureResponse.get()).isEqualTo(RespObj);
        } catch (Throwable e) {
            Assertions.assertThat(e).isInstanceOf(ExecutionException.class);
        }
    }

Answer 2

如果是 ExecutionException，您可能需要检查其原因。

    for (Future<Resp> future : futureList) {
        try {
            Resp got = future.get();
            assertValidResp(got); // check normal behavior (eg not null)
        }
        catch (ExecutionException e) {
            Throwable cause = e.getCause();
            assertAcceptedException(cause); // check for expected abnormal behavior (eg instanceof check)
        }
    }

AssertJ 断言异常抛出或结果

AssertJ assert either exception thrown or result

java

junit

future

assertions

assertj