Sql Server 2000 拼图

Question

 SELECT    Id ,
           ActionDate ,
           Operation ,
           Date ,
           [Payroll Number]    
FROM 
[dbo].[tblx]

1   2018-01-10 00:00:00.000 NEW     2018-01-30 00:00:00 X0154X
2   2018-01-10 00:00:00.000 NEW     2018-01-31 00:00:00 X0154X
3   2018-01-10 00:00:00.000 NEW     2018-02-01 00:00:00 X0154X
4   2018-01-10 00:00:00.000 DELETE  2018-02-01 00:00:00 X0154X
5   2018-01-10 00:00:00.000 NEW     2018-02-02 00:00:00 X0154X
6   2018-01-10 00:00:00.000 NEW     2018-02-11 00:00:00 X0154X

我需要 Payroll/Date 组合的基于行动日期的最新记录。所以我在 SQL 服务器 2000 上尝试了这个。但是，问题是 ROW_NUMBER() 直到 SQL 服务器 2008 才被引入。

这给了我 4 条记录而不是 5 条记录。 ID 为 4 的记录未返回，因为与操作日期相关联。

SELECT     Id ,
           ActionDate ,
           Operation ,
           Date ,
           [Payroll Number]
  FROM (SELECT *, (SELECT COUNT(*)
                   FROM dbo.tblx AS counter
                   WHERE counter.[Payroll Number] = dbo.tblx.[Payroll Number]
                    AND counter.[Date] = dbo.tblx.[Date]
                    AND  counter.ActionDate >= dbo.tblx.ActionDate) AS rn
        FROM dbo.tblx
        WHERE Status IN ( 0, 5 )
          AND Category = 'Holiday') AS r1
  WHERE r1.rn = 1

  Id  ActionDate                Operation   Date                Payroll Number
  1   2018-01-10 00:00:00.000   NEW         2018-01-30 00:00:00 X0154X
  2   2018-01-10 00:00:00.000   NEW         2018-01-31 00:00:00 X0154X
  5   2018-01-10 00:00:00.000   NEW         2018-02-02 00:00:00 X0154X
  6   2018-01-10 00:00:00.000   NEW         2018-02-11 00:00:00 X0154X

有没有办法在 SQL Server 2000 上 ROW_NUMBER() 获得这个？

Answer 1

在 window 活动前几天，您可以：

SELECT x.* 
FROM [dbo].[tblx] x
WHERE x.ActionDate = (SELECT MAX(x2.ActionDate)
                      FROM [dbo].[tblx] x2
                      WHERE x2.[Payroll Number] = x.[Payroll Number] AND
                            x2.Date = x.Date
                     );

此语法用于 MySQL、SQLite 和 MS Access 等不支持 window 函数的数据库。

如果您可以通过 id 定义 "latest"，则在子查询中使用它代替日期：

SELECT x.* 
FROM [dbo].[tblx] x
WHERE x.id = (SELECT MAX(x2.id)
              FROM [dbo].[tblx] x2
              WHERE x2.[Payroll Number] = x.[Payroll Number] AND
                    x2.Date = x.Date
             );

Answer 2

这有效但不是很好的代码或 sql。

SELECT 

             a.ActionDate ,
             a.Date ,
             a.[Payroll Number]
             , MAXC( a.id) AS ID_Required_To_Porcess

    FROM 
    [dbo].[tblx] a
    INNER JOIN ( 

    SELECT 
             x.ActionDate ,
             x.Date ,
             x.[Payroll Number]
    FROM [dbo].[tblx] x
    WHERE x.ActionDate = (SELECT MAX(x2.ActionDate)
                          FROM [dbo].[tblx] x2
                          WHERE x2.[Payroll Number] = x.[Payroll Number] AND
                                x2.Date = x.Date
                         )

    GROUP BY x.ActionDate ,
             x.Date ,
             x.[Payroll Number]


             ) b ON a.ActionDate=b.actionDate AND a.date=b.date AND a.[Payroll Number]=b.[Payroll Number]


    GROUP BY     a.ActionDate ,
             a.Date ,
             a.[Payroll Number]

Sql Server 2000 拼图

Sql Server 2000 Puzzle

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