Hibernate 继承：架构验证：缺少列

Question

我正在尝试使用策略 InheritanceType.JOINED 在 Hibernate 中实现继承。但是，在启动应用程序时失败并出现以下异常：

Caused by: org.hibernate.tool.schema.spi.SchemaManagementException: Schema-validation: missing column [EMAIL] in table [CLIENT]

我不知道它为什么要在 Client table 中寻找字段 email，因为实体模型指定它在抽象超类中 - User.客户端只有特定于它的字段。

这是我的实体模型的样子。

UserTable.java

@Entity
@Table(name = "USER")
@Inheritance(strategy = InheritanceType.JOINED)
public abstract class UserTable implements Serializable {

    private static final long serialVersionUID = 1L;

    @Column(name = "USER_ID", nullable = false)
    private Long userId;

    @EmbeddedId
    private UserTablePK userTablePK;

    @Column(name = "PASSWORD", nullable = false, length = 512)
    private String password;

    @Column(name = "FIRSTNAME", nullable = false, length = 256)
    private String firstName;

    public UserTable() {
    }

    public UserTable(Long userId, String email, String password, String firstName) {
        this.userId = userId;
        this.userTablePK = new UserTablePK(email);
        this.password = HashCalculator.calculateSha256Hash(password, SecurityConstants.saltConstant());
        this.firstName = firstName;
    }
// get, set
}

UserTablePK.java

@Embeddable
public class UserTablePK implements Serializable {

    @Column(name = "EMAIL", nullable = false, length = 256)
    private String email;

    public UserTablePK() {
    }

    public UserTablePK(String email) {
        this.email = email;
    }

ClientTable.java

@Entity
@Table(name = "CLIENT")
public class ClientTable extends UserTable implements Serializable {

    @Column(name = "WEIGHT")
    private String weight;

    @Column(name = "HEIGHT")
    private Integer height;

    public ClientTable() {
    }

    public ClientTable(Long clientId, String weight, Integer height, String email, String password, String firstName) {
        super(clientId, email, password, firstName);
        this.weight = weight;
        this.height = height;
    }
}

同样，为什么要在子类table中寻找email字段？我使用 Liquibase 生成架构，并检查了架构是否正确。 Clienttable里没有email，只有Usertable里才是应该的。实体模型对应的是那个，有什么问题吗？

Answer 1

因为它是父class中的pk ....你需要从子table引用父table，因此你还需要一个'email' 子项 table 中的列以通过它返回父项 table

编辑：您只需要在 'CLIENT' table 中添加一列 "email" 以仅使用 JPA 默认配置....如果您想编辑 FK从子项到父项的引用，您需要按照 here

中的描述覆盖 @PrimaryKeyJoinColumn

Hibernate 继承：架构验证：缺少列

Hibernate inheritance: Schema-validation: missing column

java

inheritance

hibernate

jpa

database-schema