如何在 java 保留标点符号中将字符串拆分为单词？

Question

这是输入

hello; this is cool?
great,   awesome

我希望我的输出是

hello;
this
is
cool?
great,
awesome

我基本上认为一个词里面有标点符号。这是我对我的应用程序的定义。我想根据 space、tabspace 和换行符拆分单词。大多数 Whosebug 问题和答案都假设单词不包含标点符号，那么我该如何解决这个问题？

Answer 1

直接在代码中注释和解释：

//1st possibility: every single whitespace character (space, tab, newline, carriage return, vertical tab) will be treated as a separator
String s="hello; this is cool?\ngreat,   awesome";
String[] array1 = s.split("\s");
System.out.println("======first case=====");
for(int i=0; i<array1.length; i++)
    System.out.println(array1[i]);

//2nd possibility (groups of consecutive whitespace characters (space, tab, newline, carriage return, vertical tab) will be treated as a single separator
String[] array2 = s.split("\s+");
System.out.println("=====second case=====");
for(int i=0; i<array2.length; i++)
    System.out.println(array2[i]);
//notice the difference in the output!!!

输出：

======first case=====
hello;
this
is
cool?
great,
         <----- Notice the empty string
         <----- Notice the empty string
awesome
=====second case=====
hello;
this
is
cool?
great,
awesome

如何在 java 保留标点符号中将字符串拆分为单词？

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