JDBC 分页 Oracle 一次获取 1000,然后执行下一个 1000

JDBC Pagination Oracle get 1000 at a time execute then get next 1000

我正在使用此代码一次获取 1000 条记录。它工作正常,但我如何在第 1000 运行 个工作停止,然后从我离开的地方继续并获得下一组 1001 - 2000,运行 下一个工作等等?请帮助我有点卡住了。

public class PaginationJDBC {

   public static void main(String arg) {
       for(int i=1; i<=5 ;i++){
              paginationMethod(i);
   }
}

static void paginationMethod(int n){
       Connection con = null;
       PreparedStatement ps = null;
       ResultSet rs = null;                  
       try {
              con = gettingMyConnection;
              ps = con.prepareStatement("select emp.id, emp.name  "
                + "from ( select rownum rn, e.* from EMPLOYEE e) emp "
                + "where rn >=? and rn< =? ");
              ps .setInt(1, (n*1000) -999);
              ps .setInt(2, n*1000);

              rs = prepStmt.executeQuery();
              int rowCount = 0;
              while (rs.next()) {
              ++rowCount;
                    System.out.print(rs.getInt(1)+" ");
                    System.out.println(rs.getString(2));
              if(rowCount >= 1000-4) {
               system.out.printlin("total records" + rowCount);
              //I would like to run a job here, returns the 1st 1000
               return;
              } 
              if(rowCount >= 1001) {
               **// this is where I would do the next job between 1001 and 2000 and so on, but I'm stuck**
              }

       } catch (ClassNotFoundException e) {
              e.printStackTrace();
       } catch (SQLException e) {
              e.printStackTrace();
       }
       finally{
              try {
                    if(rs!=null) rs.close(); //close resultSet
                    if(ps !=null) ps .close(); //close PreparedStatement
                    if(con!=null) con.close(); // close connection
              } catch (SQLException e) {
                    e.printStackTrace();
              }
       }

}

}

使用您的应用程序记下您到达的位置,例如,假设我要显示今天的记录,一次显示 20 行。我可能会写:

第 1 页

select * 
from T 
where date_col = trunc(sysdate) 
order by id desc
fetch first 20 rows only

我将 ID=100 提取到 80...我记下了 80。我的下一个查询将是

select * 
from T 
where date_col = trunc(sysdate) 
AND ID<80  <<==== additional predicate
order by id desc
fetch first 20 rows only

我的下一个查询是

select * 
from T 
where date_col = trunc(sysdate) 
AND ID<60
order by id desc
fetch first 20 rows only

等等。