如果方法以 invoke 启动，Exceptions 不会导致崩溃

Question

出于某种原因，如果通过 invoke() 调用方法，它抛出的未捕获异常不会导致崩溃。但是，它确实退出了该方法。 invoke 运行它是否是另一个线程（因为异常只会使线程崩溃，对吗？），如果是这样，是否有办法发送异常或其他东西？

这是一个简单的例子：

import java.lang.reflect.InvocationTargetException;

public class Main {
    public static void main(String[] args) {
        try {
            Class.forName("Main").getMethod("thrower").invoke(null);
        }
        catch (IllegalAccessException e) {}
        catch (IllegalArgumentException e) {}
        catch (ClassNotFoundException e) {}
        catch (NoSuchMethodException e) {}
        catch (InvocationTargetException e) {}
        catch (SecurityException e) {}
    }
    public static void thrower() {
        throw new RuntimeException();
    }
}

Answer 1

来自 java.lang.reflect.Method 文档：

@exception InvocationTargetException if the underlying method throws an exception.

您发现了一个 InvocationTargetException, it will be thrown with a RuntimeException 原因：

catch (InvocationTargetException e) {
    final Throwable cause = e.getCause();
    // cause.getClass().getName() = java.lang.RuntimeException
}

Answer 2

它不在单独的线程中运行。从 thrower 抛出的 RuntimeException 实际上在反射调用期间被 InvocationTargetException 包裹，随后被什么都不做的代码捕获。

请参阅 InvocationTargetException

的 Javadoc

InvocationTargetException is a checked exception that wraps an exception thrown by an invoked method or constructor. As of release 1.4, this exception has been retrofitted to conform to the general purpose exception-chaining mechanism. The "target exception" that is provided at construction time and accessed via the getTargetException() method is now known as the cause, and may be accessed via the Throwable.getCause() method, as well as the aforementioned "legacy method."

如果方法以 invoke 启动，Exceptions 不会导致崩溃

If a method is started with invoke, Exceptions do not cause a crash

java

exception

reflection

runtimeexception