Rails 不会用 nokogiri 和 open-uri 读取 link

Question

我有一个控制器，它获取一个 url 作为参数传递，我正试图在 url 处抓取整个页面。但是当我尝试阅读 url 时，出现以下错误：No such file or directory @ rb_sysopen - www.google.com

控制器：

lass PageScraperController < ApplicationController
    require 'nokogiri'
    require 'open-uri'
    require 'diffy'
    require 'htmlentities'

    def scrape
    require 'open-uri'
        @url = watched_link_params.to_s
        @url = @url.slice(9..@url.length-3)
        puts "LOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOG#{@url}"

        page = Nokogiri::HTML(open(@url))
        # coder = HTMLEntities.new
        # encodedHTML = coder.encode(page)
        puts page

     end

    def watched_link_params

        params.require(:default).permit(:url)

    end

end

Answer 1

试试这个：

def scrape
  @url = watched_link_params[:url]

  page = Nokogiri::HTML(open(@url))
  puts page
end

您需要传递整个 url，包括协议指示符；也就是说，你需要使用 http://www.google.com 而不是 www.google.com:

>> params = ActionController::Parameters.new(default: {url: 'http://www.google.com'})
>> watched_link_params = params.require(:default).permit(:url)
>> @url = watched_link_params[:url]
"http://www.google.com"
>> page = Nokogiri::HTML(open(@url))

Rails 不会用 nokogiri 和 open-uri 读取 link

Rails won't read a link with nokogiri and open-uri

ruby

open-uri

ruby-on-rails

nokogiri

ruby-on-rails-5