从多个不同的行中查找 MSSQL 中 2 个日期之间的差异

Question

当使用 MSSQL 时，有什么方法可以使用 SQL 语句对 2 个不同行的日期进行 DATEDIFF。我们正在尝试衡量响应时间。

我们有一个消息传递系统，用于存储 UniqueKey、Note、DateNoteSent 和发送笔记的用户。

数据样本：

UniqueKey      Note                 User     DateOfNote                 
L4H2390039D2   This is a test.      23       2018-01-30 16:15:14.2965479
L4H2390039D2   Test received.       15       2018-01-30 18:10:00.3482044
DH38D2DJ8382   Call me ASAP.        17       2018-01-30 16:22:34.1971033
DH38D2DJ8382   Will do.             35       2018-01-30 16:25:34.1749088
DH38D2DJ8382   Sorry I missed you.  17       2018-01-30 16:28:34.1991463

是否可以找出具有相同UniqueKey的消息中的date/times之间的区别？

有些消息在链中有超过 2 条消息，并且会。

我想要最后一列显示上一条名为 ResponseTime 的消息的持续时间，显示时间即：12:34:33 或 1 小时 37 分钟。

感谢您的帮助。

Answer 1

如果您在 2012 年之前使用 SQL，那么替代 LEAD 函数：

create Table #Table1 (
    UniqueKey varchar(20),
    Note varchar(100),
    [User] varchar(10),
    DateOfNote datetime
    );

-- add some records 
Insert into #Table1 (UniqueKey,Note,[User],DateOfNote) values  ('L4H2390039D2','This is a test.','23',CAST(N'2018-01-30 16:15:14.296' AS DateTime))
Insert into #Table1 (UniqueKey,Note,[User],DateOfNote) values  ('L4H2390039D2','Test received.','15',CAST(N'2018-01-30 18:10:00.348' AS DateTime))
Insert into #Table1 (UniqueKey,Note,[User],DateOfNote) values  ('DH38D2DJ8382','Call me ASAP','17',CAST(N'2018-01-30 16:22:34.197' AS DateTime))
Insert into #Table1 (UniqueKey,Note,[User],DateOfNote) values  ('DH38D2DJ8382','Will do.','35',CAST(N'2018-01-30 16:25:34.174' AS DateTime))
Insert into #Table1 (UniqueKey,Note,[User],DateOfNote) values  ('DH38D2DJ8382','Sorry I missed you.','17',CAST(N'2018-01-30 16:28:34.199' AS DateTime))
Insert into #Table1 (UniqueKey,Note,[User],DateOfNote) values  ('DH38D2DJ8382','Sorry I missed you.','17',CAST(N'2018-02-02 08:01:34.199' AS DateTime))


select t.Number,t.UniqueKey,t.DateofNote,tnext.DateofNote,datediff(minute, t.DateofNote, tnext.DateofNote) as DiffMinutes,CONVERT(varchar(12), 
       DATEADD(minute, DATEDIFF(minute, t.DateofNote, tnext.DateofNote), 0), 114) as hourMinute,
        cast(datediff(minute, t.DateofNote, tnext.DateofNote) / 1440 as varchar) + ' days ' + cast((datediff(minute, t.DateofNote, tnext.DateofNote) % 1440) / 60  as varchar) + ' hours ' + cast(datediff(minute, t.DateofNote, tnext.DateofNote) % 60 as varchar) + ' minutes' as DaysHoursMinutes

from (
select * 
,ROW_NUMBER() over ( ORDER BY UniqueKey,DateOfNote) AS Number
from #Table1 

)t join
     (select * 
,ROW_NUMBER() over ( ORDER BY UniqueKey,DateOfNote) AS Number
from #Table1 

) tnext
     on t.Number = tnext.Number - 1 and t.UniqueKey = tnext.UniqueKey
order by t.UniqueKey,t.DateofNote

Answer 2

这是一个使用 LAG 函数的解决方案。结果的格式为 hhh:mm:ss

select
    UniqueKey, Note, [User], DateOfNote
    , concat(right(concat('000',diff/3600), 3), ':', right(concat('00',diff%3600/60), 2), ':', right(concat('00',diff%60), 2))
from (
    select 
        *, diff = datediff(ss, lag(DateOfNote) over (partition by UniqueKey order by DateOfNote), DateOfNote)
    from 
        #Table1
) t

从多个不同的行中查找 MSSQL 中 2 个日期之间的差异

Finding the Difference between 2 Dates in MSSQL from multiple different Rows

sql-server

datediff

messages