使用 es6 将嵌套对象中的 props 合并为一个对象

Question

假设我们有以下内容：

const Patients = {
  P1: {
    "name": "Person1",
    "profession": "Student",
    "gender": "Male",
    "type": "Patient",
    "Doctors": {...}
  },
  P2: {
    "name": "Person2",
    "profession": "Student",
    "gender": "Male",
    "type": "Patient",
    "Doctors": {...}
  }
}

const Doctors = {
  D1: {
    "name": "Doctor1",
    "profession": "Dr",
    "gender": "Male",
    "type": "Doctor",
    "Patients": {...}
  }
}

我们如何将两个对象（患者和医生）合并为一个对象，以便结果如下：

const Result = {
  "name": "Doctor1",
  "profession": "Dr",
  "Patients": {...},
  P1: {
    "Doctors": {...}
  },
  P2: {
    "Doctors": {...}
  }
}

据我所知，我可以对两个对象使用 destruct 来部分破坏并形成一个新对象。但这使得获取嵌套对象变得更加困难（即 P1 和 P2 中的 "Doctors": {...}。

例如：

let result = (({
      name,
      profession,
      Patients
    }, { /* Im not sue what to do here */ }) => ({
      Patients,
      /* Im not sue what to do here */ ))(Doctor, Object.values(Patients));

Answer 1

使用扩展语法 ... 和 reduce 函数。

const Patients = {  P1: {    "name": "Person1",    "profession": "Student",    "gender": "Male",    "type": "Patient",    "Doctors": {}  },  P2: {    "name": "Person2",    "profession": "Student",    "gender": "Male",    "type": "Patient",    "Doctors": {}  }}
const Doctors = {  D1: {    "name": "Doctor1",    "profession": "Dr",    "gender": "Male",    "type": "Doctor",    "Patients": {}  }}

var result = { ...Doctors.D1,
  ...Object.keys(Patients).reduce((a, k) => {
    a[k] = {
      "Doctors": Patients[k].Doctors
    };
    return a;
  }, {})
};

delete result.gender;
delete result.type;

console.log(result);

.as-console-wrapper {
  max-height: 100% !important
}

使用 es6 将嵌套对象中的 props 合并为一个对象

merge props from nested objects as one single object using es6

javascript

object

object-properties

ecmascript-6

spread-syntax