从 SQL 问题生成 XML

Question

我需要生成如下格式的XML:

任务的xml部分我还没有走得太远，遇到了下面的情况，你可以看出这显然不是我的本意。

How can I handle this properly considering that BBAN and IBAN need to be inside AccountNoas well as that I want it formatted according to the first picture.

完整的查询以及我生成 xml 的公平尝试如下所示：

DECLARE @AccountType NVARCHAR(3);
DECLARE @kodBanke NVARCHAR(3);

SET @AccountType = 'T';
SET @kodBanke = ( SELECT vrednost FROM dbini WHERE IDENT = 'KOD' AND SECTION = 'PP' );

WITH Ent_Posta
AS
(
    SELECT e.naziv,p.posta,e.sifra
    FROM entitet AS e
         INNER JOIN poste AS p ON e.sifra = p.entitet
)
SELECT (
  SELECT 
    [dbo].[brojracuna](@kodBanke,i.partija) AS 'BBAN',
    [dbo].[GENERATEIBAN](i.partija) AS 'IBAN'
     FOR XML PATH('AccountNo'), ELEMENTS, ROOT('Account')
     ),
    @accountType AS 'AccountType',
    (a.ime + ' ( ' + a.roditel + ' ) ' + a.prezime) AS 'Name',
    a.embg AS 'UID',
    CASE status 
       WHEN 2 THEN 'A' 
       WHEN 4 THEN 'B'
       WHEN 8 THEN 'U'
    END AS 'Status',
     c.sifra AS 'Territory',
     @kodBanke as 'ID_Bank',
   REPLACE(CONVERT(VARCHAR(10), i.DOTVaRANJE, 120), '.', '') + '-' + RIGHT( '0' + CONVERT(VARCHAR(2), DATEPART(hh, i.DOTVaRANJE)), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2), DATEPART(mi, i.DOTVaRANJE)), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2), DATEPART(s, i.DOTVaRANJE)),2) AS OpeningDate,

   REPLACE(CONVERT(VARCHAR(10),'2006.09.28 ', 120), '.', '') + '-' + RIGHT( '0' + CONVERT(VARCHAR(2), DATEPART(hh, '2006.09.28' )), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2), DATEPART(mi, '2006.09.28 ')), 2) + '' + RIGHT('0' + CONVERT(VARCHAR(2),DATEPART(s,'2006.09.28 ')),2) AS ClosingDate
     FROM adresar AS a
  INNER JOIN istdden AS i 
      ON a.embg = i.embg
        INNER JOIN Ent_Posta as c
        ON a.postbroj = c.posta
           FOR XML PATH ('Account'), ROOT('Accounts');

删除 this part 我得到...

<Accounts>
  <Account>
    <BBAN>5710543102313248</BBAN>
    <IBAN>BA39531231634039248</IBAN>
    <AccountType>T</AccountType>
    <Name>DARKO ( DRAGAN ) TESIC</Name>
    <UID>0000005467234</UID>
    <Status>A</Status>
    <Territory>1</Territory>
    <ID_Bank>571</ID_Bank>
    <OpeningDate>20081205-000000</OpeningDate>
    <ClosingDate>20060928-000000</ClosingDate>
  </Account>

...但现在缺少 AccountNO。

Answer 1

你的问题不是很清楚，但是 - 如果我没听错 - 你正在与 1:1 值作斗争，但在更深的嵌套中。

您可以在 [] 中使用类似 XPath 的表达式来连接 FOR XML PATH。看看这个：

SELECT 'blah' AS FirstNode
      ,'blub' AS [SecondNode/OneDeeper]
      ,'blib' AS [SecondNode/OneMore]
      ,'ballaballa' AS [ThirdNode]
FOR XML PATH('row'),ROOT('root');

结果（特别看<SecondNode>:

<root>
  <row>
    <FirstNode>blah</FirstNode>
    <SecondNode>
      <OneDeeper>blub</OneDeeper>
      <OneMore>blib</OneMore>
    </SecondNode>
    <ThirdNode>ballaballa</ThirdNode>
  </row>
</root>

如果这不是您需要的，请标记实际的 RDBMS（产品 和版本 ）并阅读 How to ask a good SQL question and How to create a MCVE

对于您的问题，在查询中使用 AS [AccountNo/IBAN] 可能就足够了。

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