在 PHP 中使用 XMLDOm 查找节点的值
Finding value of nodes using XMLDOm in PHP
我需要使用 XMLDom 从 XML 中提取信息。
下面是myroot.xml
<?xml version='1.0' encoding='ISO-8859-1'?>
<myroot xml:lang='en'>
<delta>
<history>
<detail>
<id>one</id>
<degree>
<dname>alpha</dname>
<dates>
<StartDate>
<Year>1998</Year>
</StartDate>
<EndDate>
<Year>2002</Year>
</EndDate>
</dates>
</degree>
</detail>
<detail>
<id>two</id>
<degree>
<dname>beta</dname>
<dates>
<StartDate>
<Year>2006</Year>
</StartDate>
<EndDate>
<Year>2008</Year>
</EndDate>
</dates>
</degree>
</detail>
</history>
</delta>
这是我的代码
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$rootxmldoc = $doc->load('myroot.xml');
$xpath = new DOMXPath($rootxmldoc);
$items = $hrxml_obj->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$query = "//dates/*/Year"; //xpath of all occurrence of Year
$entries = $xpath->query($query, $item);
foreach ($entries as $entry) {
$dates["startdate"] = "todo"; //extract StartDate
$dates["enddate"] = "todo"; //extract EndDate
}
$subitemarray[$icounter++] = dates;
}
var_dump($subitemarray);
理想情况下,我需要使用 xpath 提取日期。我无法解决这个问题。任何帮助表示赞赏。问题是循环时 xpath 的使用。
使用 XPath 直接转到 dates
标记,然后使用 DOMElement::getElementsByTagName()
to get StartDate
and EndDate
(you can also go to the dates
tag using DOMDocument::getElementsByTagName()
, but XPath gives you more flexibility should you need it). This will return a DOMNodeList
,但您知道(如果结构不变)您只需要列表的第一个元素。所以:
// $xml ommited, saved in a variable for testing purposes
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadXML($xml);
$xpath = new DOMXPath($doc);
$items = $doc->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$query = "//dates"; //xpath of all occurrence of Year
$entries = $xpath->query($query, $item);
foreach ($entries as $entry) {
$startDate = $entry->getElementsByTagName("StartDate")[0]->nodeValue;
$endDate = $entry->getElementsByTagName("EndDate")[0]->nodeValue;
$dates["startdate"] = $startDate; //extract StartDate
$dates["enddate"] = $endDate; //extract EndDate
}
$subitemarray[$icounter++] = $dates;
}
var_dump($subitemarray);
或仅使用 XPath:
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadXML($xml);
$xpath = new DOMXPath($doc);
$items = $doc->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$queryStart = "//dates/StartDate";
$entriesStart = $xpath->query($queryStart, $item);
$dates["startdate"] = $entriesStart[0]->nodeValue;
$queryEnd = "//dates/EndDate";
$entriesEnd = $xpath->query($queryEnd, $item);
$dates["enddate"] = $entriesEnd[0]->nodeValue;
$subitemarray[$icounter++] = $dates;
}
var_dump($subitemarray);
最后,只使用一个 XPath 查询:
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadXML($xml);
$xpath = new DOMXPath($doc);
$items = $doc->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$query = "//dates/*[contains(local-name(), 'Date')]
";
$entries = $xpath->query($query, $item);
$dates["startdate"] = $entries[0]->nodeValue;
$dates["enddate"] = $entries[1]->nodeValue;
$subitemarray[$icounter++] = $dates;
}
var_dump($subitemarray);
查询将只获取当前 detail
元素中包含单词 "Date" 的所有元素。同样,如果结构不变,您可以假设第一个结果为 StartDate
,第二个结果为 EndDate
.
我需要使用 XMLDom 从 XML 中提取信息。
下面是myroot.xml
<?xml version='1.0' encoding='ISO-8859-1'?>
<myroot xml:lang='en'>
<delta>
<history>
<detail>
<id>one</id>
<degree>
<dname>alpha</dname>
<dates>
<StartDate>
<Year>1998</Year>
</StartDate>
<EndDate>
<Year>2002</Year>
</EndDate>
</dates>
</degree>
</detail>
<detail>
<id>two</id>
<degree>
<dname>beta</dname>
<dates>
<StartDate>
<Year>2006</Year>
</StartDate>
<EndDate>
<Year>2008</Year>
</EndDate>
</dates>
</degree>
</detail>
</history>
</delta>
这是我的代码
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$rootxmldoc = $doc->load('myroot.xml');
$xpath = new DOMXPath($rootxmldoc);
$items = $hrxml_obj->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$query = "//dates/*/Year"; //xpath of all occurrence of Year
$entries = $xpath->query($query, $item);
foreach ($entries as $entry) {
$dates["startdate"] = "todo"; //extract StartDate
$dates["enddate"] = "todo"; //extract EndDate
}
$subitemarray[$icounter++] = dates;
}
var_dump($subitemarray);
理想情况下,我需要使用 xpath 提取日期。我无法解决这个问题。任何帮助表示赞赏。问题是循环时 xpath 的使用。
使用 XPath 直接转到 dates
标记,然后使用 DOMElement::getElementsByTagName()
to get StartDate
and EndDate
(you can also go to the dates
tag using DOMDocument::getElementsByTagName()
, but XPath gives you more flexibility should you need it). This will return a DOMNodeList
,但您知道(如果结构不变)您只需要列表的第一个元素。所以:
// $xml ommited, saved in a variable for testing purposes
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadXML($xml);
$xpath = new DOMXPath($doc);
$items = $doc->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$query = "//dates"; //xpath of all occurrence of Year
$entries = $xpath->query($query, $item);
foreach ($entries as $entry) {
$startDate = $entry->getElementsByTagName("StartDate")[0]->nodeValue;
$endDate = $entry->getElementsByTagName("EndDate")[0]->nodeValue;
$dates["startdate"] = $startDate; //extract StartDate
$dates["enddate"] = $endDate; //extract EndDate
}
$subitemarray[$icounter++] = $dates;
}
var_dump($subitemarray);
或仅使用 XPath:
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadXML($xml);
$xpath = new DOMXPath($doc);
$items = $doc->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$queryStart = "//dates/StartDate";
$entriesStart = $xpath->query($queryStart, $item);
$dates["startdate"] = $entriesStart[0]->nodeValue;
$queryEnd = "//dates/EndDate";
$entriesEnd = $xpath->query($queryEnd, $item);
$dates["enddate"] = $entriesEnd[0]->nodeValue;
$subitemarray[$icounter++] = $dates;
}
var_dump($subitemarray);
最后,只使用一个 XPath 查询:
$doc = new DOMDocument;
$doc->preserveWhiteSpace = false;
$doc->loadXML($xml);
$xpath = new DOMXPath($doc);
$items = $doc->getElementsByTagName("detail");
$subitemarray = array();
$icounter = 0;
foreach ($items as $item) {
$query = "//dates/*[contains(local-name(), 'Date')]
";
$entries = $xpath->query($query, $item);
$dates["startdate"] = $entries[0]->nodeValue;
$dates["enddate"] = $entries[1]->nodeValue;
$subitemarray[$icounter++] = $dates;
}
var_dump($subitemarray);
查询将只获取当前 detail
元素中包含单词 "Date" 的所有元素。同样,如果结构不变,您可以假设第一个结果为 StartDate
,第二个结果为 EndDate
.