如果资源服务器应该是无状态的，如何使用 websocket 将消息发送到队列

Question

我目前在消息传递系统中工作，其中资源服务器使用 oAuth 2 是无状态的。现在，我必须使用队列向单个用户发送消息，但问题是 spring 消息传递需要一个会话other 发送消息，如 .

中所述

我的问题是如何在无状态 restful 服务中获取当前登录用户：

@MessageMapping("/messaging")
public void messaging( Message<Object> message) {
    Principal user=    
        message.getHeaders()
             .get(SimpMessageHeaderAccessor.USER_HEADER,Principal.class); 

        messageTemplate.convertAndSend("/topic/users", user.getName());
}

当我们使用 simpMessagingTemplate.convertAndSendToUser(...) 方法并传递与会话 ID 关联的用户名时，

Spring 将使用队列。否则它将使用一个主题，所有订阅的客户端最终将读取从服务器返回的相同消息。

因为我在资源服务器中没有会话，需要排队向个人发送消息user.Any 评论和想法表示赞赏

Answer 1

终于找到解决办法了。通过为用户名解码 json 网络令牌并为用户名提供身份验证解决上述问题。 JwtAuthentication 是自定义的 class，它负责解码 JWT 并为 JWT

的用户名提供身份验证

@Configuration
@EnableWebSocketMessageBroker
@Order(Ordered.HIGHEST_PRECEDENCE + 99)
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {

    @Autowired
    private SimpUserRegistry userRegistry;

    @Override
    public void configureMessageBroker(MessageBrokerRegistry config) {
        config.enableSimpleBroker("/topic","/queue");
        // use the /app prefix for others
        config.setApplicationDestinationPrefixes("/app");
    }

    @Autowired
    private JwtAuthentication jwtAuthentication;

    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        // use the /messaging endpoint (prefixed with /app as configured above) for incoming requests
        registry.addEndpoint("/messaging").setAllowedOrigins("http://localhost:8080").withSockJS();
    }

    @Override
    public void configureClientInboundChannel(ChannelRegistration registration) {
        registration.setInterceptors(new ChannelInterceptorAdapter() {
            @Override
            public Message<?> preSend(Message<?> message, MessageChannel channel) {
                StompHeaderAccessor accessor =
                        MessageHeaderAccessor.getAccessor(message, StompHeaderAccessor.class);
                List<String> tokenList = accessor.getNativeHeader("Authorization");
                String token = null;
                if(tokenList != null && tokenList.size() > 0) {
                  token = tokenList.get(0).replaceAll("Bearer", "").trim();
                }
                if (StompCommand.CONNECT.equals(accessor.getCommand()) || StompCommand.SUBSCRIBE.equals(accessor.getCommand()) || StompCommand.SEND.equals(accessor.getCommand()) ) {
                    Authentication auth =  SecurityContextHolder.getContext().getAuthentication();
                    if(auth==null){
                         Authentication user = jwtAuthentication.getAuthentication(token); // access authentication header(s)
                         SecurityContextHolder.getContext().setAuthentication(user);
                          ((DefaultSimpUserRegistry) userRegistry).onApplicationEvent(new SessionConnectedEvent(this, (Message<byte[]>) message, auth));
                         accessor.setUser(user);
                    } else {
                        accessor.setUser(auth);
                         ((DefaultSimpUserRegistry) userRegistry).onApplicationEvent(new SessionConnectedEvent(this, (Message<byte[]>) message, auth));
                    }
                }
                accessor.setLeaveMutable(true);
                return MessageBuilder.createMessage(message.getPayload(), accessor.getMessageHeaders());
            }
        });
    }
}

在应用程序上下文中，我们需要注册 SimpUserRegistry @豆 @基本的 public SimpUserRegistry userRegistry() { return 新的 DefaultSimpUserRegistry()； }

      @Bean
      @Primary
      public UserDestinationResolver userDestinationResolver() {
        return new DefaultUserDestinationResolver(userRegistry());
      }

现在我们可以向特定用户发送消息

public void handle(Exchange exchange) {
        Message camelMessage = exchange.getIn();
        com.livetalk.user.utils.Message message = camelMessage.getBody( com.livetalk.user.utils.Message.class);
        // send the message specifically to the destination user by using STOMP's user-directed messaging
        msgTemplate.convertAndSendToUser(message.getRecipient(), "/queue/messages", message, defaultHeaders);
    }

如果资源服务器应该是无状态的，如何使用 websocket 将消息发送到队列

If resource server are supposed to be stateless, how to send message to queue with websocket

spring

spring-messaging

spring-websocket

spring-oauth2