如何拆分 Python 中的长 f 字符串?
How can I split up a long f-string in Python?
我收到一个 行太长 PEP 8 E501 问题。
f'Leave Request created successfully. Approvers sent the request for approval: {leave_approver_list}'
我尝试使用多行字符串,但这会带来 \n
,这会破坏我的测试:
f'''Leave Request created successfully.
Approvers sent the request for approval: {leave_approver_list}'''
如何让它保持单行并通过 PEP 8 linting?
除非将字符串括在括号中,否则您将需要换行符。在这种情况下,需要将 f
添加到第二行:
'Leave Request created successfully.'\
f'Approvers sent the request for approval: {leave_approver_list}'
这是一个小演示:
In [97]: a = 123
In [98]: 'foo_'\
...: f'bar_{a}'
Out[98]: 'foo_bar_123'
我推荐 ,因为它更干净,但这是一种方法。
使用括号和 string literal concatenation:
msg = (
f'Leave Request created successfully. '
f'Approvers sent the request for approval: {leave_approver_list}'
)
请注意,第一个文字不需要 f
,但我将其包含在 consistency/readability 中。
我收到一个 行太长 PEP 8 E501 问题。
f'Leave Request created successfully. Approvers sent the request for approval: {leave_approver_list}'
我尝试使用多行字符串,但这会带来 \n
,这会破坏我的测试:
f'''Leave Request created successfully.
Approvers sent the request for approval: {leave_approver_list}'''
如何让它保持单行并通过 PEP 8 linting?
除非将字符串括在括号中,否则您将需要换行符。在这种情况下,需要将 f
添加到第二行:
'Leave Request created successfully.'\
f'Approvers sent the request for approval: {leave_approver_list}'
这是一个小演示:
In [97]: a = 123
In [98]: 'foo_'\
...: f'bar_{a}'
Out[98]: 'foo_bar_123'
我推荐
使用括号和 string literal concatenation:
msg = (
f'Leave Request created successfully. '
f'Approvers sent the request for approval: {leave_approver_list}'
)
请注意,第一个文字不需要 f
,但我将其包含在 consistency/readability 中。