JavaScript ES6 - 这是扩展语法还是剩余语法？

Question

我想尽可能多地了解它是如何工作的——尤其是因为它与三元的用法和包含两个展开的对象参数有关。

rows = rows.map(row => (changed[row.ID] ? { ...row, ...changed[row.ID] } : row));

首先 - 传递到地图中的对象的结构如下： changed的形状是这样的{"75864":{"ActType":"DEADLINE"}}

rows 格式如下（例如）：

[{
    "ID": 75864,
    "NextDate": "2018-03-02T00:00:00",
    "NextTime": "1030am",
    "MatterID": 14116,
    "Descr": " Responses to pending discovery",
    "StatusID": 19,
    "Actor_s_": null,
    "Accrued": 0,
    "Go": "",
    "AspNetUserID": null,
    "DomainID": 2,
    "UserID": 1,
    "StatusType": "Pending",
    "ActTypeID": 50,
    "ActType": "DEADLINE",
    "MatterName": "WYNBAS                   "

Answer 1

如果 row.ID 值与 changed 对象中具有 "truthy" 值的键匹配，

然后你 return 一个新对象，具有 row 的所有值（你展开 row），然后将匹配 row 的值添加到这个新对象=11=] 对象（你传播了 changed 的真值）。

否则你只需 return 给定的行。

这是您要找的答案吗？

Answer 2

这是"merging" row 和changed[row.ID] 成一个对象。让我们看看当 row 是 ID 为“75864”的那个时会发生什么：

// row: {"ID": 75864, "ActType": "DEADLINE", (more properties)}
// changed: {"75864": {"ActType": "OTHER ACTION"}}
// (Note - I changed `changed` so that the ActType specified is different from
//  what's already in the row object, otherwise it's really difficult for me to
//  demonstrate exactly what's happening here.)

// This is the body of the arrow function:
return changed[row.ID] ? { ...row, ...changed[row.ID] } : row

// Well, changed[row.ID] does exist:
// changed[row.ID]: {"ActType": "OTHER ACTION"}

// So we take this branch of the ternary:
return { ...row, ...changed[row.ID] }

// Basically, this expression works like an array spread, but for objects.
// As a refresher, here's what an array spread might look like:
//
// a = [1, 2, 3]
// b = ['cat', 'dog', 'armadillo']
// c = [...a, ...b]
// c: [1, 2, 3, 'cat', 'dog', 'armadillo']
//
// The array spread works by creating a completely new, empty array. Then
// it adds the items of each array that's spread into it; so first it adds
// all the items of a (1, 2, 3), then all the items of b (cat, dog, armadillo).

// Object spread works pretty much the same way. First we create a completely
// new object: {}.
// Then we add all the properties of row: {ID: 75864, ActType: "DEADLINE",
// "MatterID": 14116, (more properties)}.
// Then it adds the the properties of changed[row.ID]. This is the important
// part, because changed[row.ID] actually *overwrites* any properties that
// we've already added from "row". This makes the result look like this:
return {ID: 75864, ActType: "OTHER ACTION", MatterID: 14116, (more properties)}

// Note that the return value's ActType property is OTHER ACTION, not DEADLINE!

请注意，对象展开本质上与使用 Object.assign 并将空对象作为第一个参数相同。（Object.assign 从第二个、第三个等参数中获取所有属性，并将它们设置在第一个参数上。这意味着它实际上改变了 - 变异 - 它的第一个参数；在这里，我们没有变异 row，我们将返回一个全新的对象 ，基于 row（和 changed[row.ID]）。）所以用 Object.assign 编写代码看起来像这个：

return Object.assign({}, row, changed[row.ID])

JavaScript ES6 - 这是扩展语法还是剩余语法？

JavaScript ES6 - Is this spread syntax or rest syntax?

javascript

ecmascript-6

spread-syntax