Laravel 5.6 路线

Question

This is the mean problem
I have controllers structures like this 

And i am using this syntax to make routes which is worked good for me

And i calling url in this way

{{ route('admin.categories.show', [$category->id]) }}

i got this error 

Any Solution ?? thanks in advance guys

Answer 1

解决方案是

{{ route('categories.show', [$category->id]) }}

跳过管理员谢谢大家。

Answer 2

分组路由时，可以通过添加标志 as:

为它们命名空间

Route::group(['prefix' => 'admin', 'as' => 'admin.'], function (){
    Route::resource('categories', 'Admin/CategoryController');
});

现在 route('admin.categories.show') 应该可以访问了。