MIPS 中的语法错误?

Syntax error in MIPS?

所以,我目前正在为我的大学学位学习 MIPS,我遇到了一个困扰我的语法错误,我似乎无法指出我哪里出错了,我的代码是用户输入两个数字的地方,控制台应该 return 一组数字,由于用户输入的两个数字,这些数字递增并完成打印,我目前在 PCSpim 上遇到语法错误,其中说 "spim: (parser) syntax error on line 55 of file" 第 55 行是我要发送的代码的 addi $t0, $t0, $t2,如果有人能指出我解决这个问题的大致方向,那就太好了。

.data
 text: .asciiz "Enter any number: "
 message: .asciiz " After while loop is done "
 str: .asciiz "Enter a number to add: "
 newline: .asciiz "\n"
 space: .asciiz ","

.text

 main:


# Printing out the text
li $v0, 4
la $a0, text
syscall

# Getting user input
li $v0, 5
syscall

# Moving the integer input to another register
move $t1, $v0

# Printing out the newline
li $v0, 4
la $a0, newline
syscall

# Printing out the text
li $v0, 4
la $a0, str
syscall

# Getting user input
li $v0, 5
syscall

# Moving the integer input to another register
move $t2, $v0

# Printing out the newline
li $v0, 4
la $a0, newline
syscall

 # i = 0

 addi $t0, $zero, 0

 while: 

 bgt $t0, $t1, exit
 jal printNumber

 addi $t0, $t0, $t2

 j while

 exit:
    li $v0, 4
    la $a0, message
    syscall

 #End of program
 li $v0, 10
 syscall

 printNumber:
   la $v0, 1
   add $a0, $t0, $zero
   syscall

   li $v0, 4
   la $a0, space
   syscall

   jr $ra

看起来 addi 需要第三个值是立即值而不是寄存器...如果它是寄存器,它应该是 add