xpath如何按位置访问节点

Question

我有这样的xml文件

<ce:MarkInfo>
<ce:boxpos>
<ce:boxnumber>box-00112</ce:boxnumber>
<ce:amclist>
<ce:amc>12</ce:amc>
<ce:amc>22</ce:amc>
</ce:amclist>
</ce:boxpos>
<ce:boxpos>
<ce:boxnumber>box-00113</ce:boxnumber>
<ce:amclist>
<ce:amc>32</ce:amc>
<ce:amc>42</ce:amc>
<ce:amc>52</ce:amc>
<ce:amc>62</ce:amc>
</ce:amclist>
</ce:boxpos>
</ce:MarkInfo>

和 xpath 表达式

xDoc.selectNodes("/ns:Documents/ns:Document/ns:WayBill_v3/wb:Content/wb:Position[1]/wb:InformF2/ce:MarkInfo//ce:amc").length = 6

/ns:Documents/ns:Document/ns:WayBill_v3/wb:Content/wb:Position[1]/wb:InformF2/ce:MarkInfo//ce:amc[1]

returns AMC值以12开头

/ns:Documents/ns:Document/ns:WayBill_v3/wb:Content/wb:Position[1]/wb:InformF2/ce:MarkInfo//ce:amc[3]

returns AMC值以52开头

/ns:Documents/ns:Document/ns:WayBill_v3/wb:Content/wb:Position[1]/wb:InformF2/ce:MarkInfo//ce:amc[5]

returns 空

如何通过节点的绝对位置而不是在 ce:amclist 中的位置访问节点？

Answer 1

"how can i access nodes by they absolute position, not by position in ce:amclist?"

将整个 XPath 包裹在括号中，并在外面添加位置谓词：

(/ns:Documents/.....//ce:amc)[5]

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msxml6