生成一天属于哪个 15 天的时间段

Generate which 15-days period a day fall into

我有一个包含年份和日期的数据框

df <- data.frame(year = rep(1980:2015,each = 365), day = 1:365)

请注意,我一年只需要 365 天,即我假设每一天都有 365 年。

我要生成两个数据: 1)每一天属于哪个月 2) 每一天属于哪15天。一年有24个15天。也就是说,每个月都会像这样分成两半;

     Jan: 1st - 15th: 1st Quarter
     Jan: 16th- 31st: 2nd Quarter
     Feb: 1st - 15th: 3rd Quarter
     Feb: 16th - 28th: 4th Quarter
     March: 1st - 15th: 5th Quarter
     .
     .
     Decmber: 16th - 31st: 24th quarter

我的最终数据应该是这样的

       Year Day  Quarter   Month
       1980  1    1          1
       1980  2    1          1
        .
        .
       1980  365   24        12
        . 
        .
       2015  1    1          1
       2015  2    1          1
        .
        .
       2015  365   12        24

我可以用这个生成月份:

   library(dplyr)
   months <- list(1:31, 32:59, 60:90, 91:120, 121:151, 152:181, 182:212, 213:243, 244:273, 274:304, 305:334, 335:365)

    df1 <- df %>% group_by(year) %>% 
          mutate(month = sapply(day, function(x) which(sapply(months, function(y) x %in% y)))

但是我不知道15天的期限是怎么产生的?

为了处理不应包括闰年的 2 月 29 日的问题,我们可能会生成一个完整的日期序列,然后删除 2 月 29 日的实例。从日期中获取 month。通过检查 %d 是否为 <= 15 并从 2* 中减去月份数来计算 two-week 周期。

# complete sequence of dates
# use two years in this example, with 2012 being a leap year
dates <- data.frame(date = seq(as.Date("2011-01-01"), as.Date("2012-12-31"), by = "1 day"))

# remove Feb 29th in leap years
d <- dates[format(dates$date, "%m-%d") != "02-29", , drop = FALSE]

# create month
d$month <- month(d$date)

# create two-week number
d$twoweek <- d$month * 2 - (as.numeric(format(d$date, "%d")) <= 15)