如何测试字符串是否有数组条目

Question

我正在用 Discord.js 创建一个 Discord 机器人，只要有人在消息中发誓，它就会捕捉到。我有一个数组，其中充满了我希望它能捕捉到的常见脏话、缩写、种族和性辱骂等。

const SwearWords = ["a##","ba##ard","bi###","c#ck","c#nt","d#ck","f#ck","gay","k#ke","n#gg","omfg","sh#t","wtf"];

（该数组没有所有主题标签，我只是为 post 添加了它们）

我最初尝试使用的是if (lcMsg.includes(SwearWords)) {return;}，lcMsg是message.content.toLowerCase();，这样无论用户如何大写，它都能抓住用户的脏话。但这没有用，所以我尝试在 Google-ing 答案后使用 .entries() 和 .every()（但我从未找到任何答案）。

我想 .map() 行得通吗？我不知道，因为我还没有学会如何使用它。如果有人能帮我解决这个问题那就太好了。

Answer 1

数组.some方法在这里会有帮助。将它与您的 .includes 结合起来，看看邮件中是否出现了这些词：

const SwearWords = ["a##","ba##ard","bi###","c#ck","c#nt","d#ck","f#ck","gay","k#ke","n#gg","omfg","sh#t","wtf"];

const saltyMessage = "wtf, git gud scrub";
const niceMessage = "gg wp";

function hasBadWord(msg) {
    return SwearWords.some(word => msg.includes(word));
}

console.log("Message and has swear word?:", saltyMessage, " -> ", hasBadWord(saltyMessage));
console.log("Message and has swear word?:", niceMessage, " -> ", hasBadWord(niceMessage));

此外，您可以使用 .find 而不是 .some 来查找消息包含的单词：

const SwearWords = ["a##","ba##ard","bi###","c#ck","c#nt","d#ck","f#ck","gay","k#ke","n#gg","omfg","sh#t","wtf"];

const saltyMessage = "wtf, git gud scrub";
const niceMessage = "gg wp";

function whichBadWord(msg) {
    return SwearWords.find(word => msg.includes(word));
}

console.log("Message and has swear word?:", saltyMessage, " -> ", whichBadWord(saltyMessage));
console.log("Message and has swear word?:", niceMessage, " -> ", whichBadWord(niceMessage));

Answer 2

您需要使用函数some和函数includes

lcMsg.replace(/\s+/g, ' ').split(' ').some((w) => SwearWords.includes(w));

看看变量 lcMsg 是如何准备循环它的词的。

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